Partnered Output Coils - Free Energy

[tinman]

Chris,

You have referenced the Preva device previously and indicated there were unique operating properties to the device as shown in his video, so I decided to replicate using a ferrite core wound with three identical windings and operating at 15KHz.  The schematic is attached below and shows all probe connections for identification in the scope pix also attached below.

Referring first to the "Preva Test w_2x100 Ohm Load", the Math(red) channel indicates the true input power to be 1.183 watts.  CH2(blu) is the voltage across R1 and is seen to be 4.793v rms which calculates to .2297 watts.  CH3(pnk) shows 9.766v rms across R2 which calculates to .9537 watts for a total output of 1.1834 watts for a COP = .999.  Very efficient but I see no evidence of OU here.

Referring next to "Preva Test w_2x100 Ohm Load KCL" we examine the currents in the circuit to see if there is any violation of KCL.  The reference channels R1 and R2 are stored current measurements for loads resistors R1 and R2 respectively.  The Math(red) channel shows the sum of the ref currents R1/R2 while accounting for phase and show the result to be 51.16ma rms.  This is extremely close to the input current shown on CH4 which is 51.38ma.  Therefore, I see no evidence of any violation of KCL with the device when operating with loads.  In fact, it can be shown that KCL is also not violated without any loads connected. 

So, IMO the Preva device is a very efficient transformer which is no small feat, but not OU!

pm

pm

Could you also calculate and include the power being dissipated by L1,L2 and L3 ?
This always seems to be forgotten when P calculations are being made.


Brad

[hyiq]

Re-Reading, back on my post, I see I was not very clear, not very accurate in some of the terms I meant - I apologise for not being able to get things out as I mean sometimes.

When I say some things, I try to leave open Questions, as if to say more investigation is needed, and the terminology I used in this post is not as I would have liked:

In L2, Using Ohms law, and also verifying the Phase angle Correction through a Resistance, being Zero Degrees, mentioned above, we can calculate the Power across the Resistance: Power P = Resistance R * Current I² = 2.3 Ohms (2.2 + 0.1) * 0.54700816 Amps = 1.28925 Watts, which means that a Voltage V across the Resistance R is only 1.722 Volts, verified on the scope, but on the other side of the Inductor, there is 12,54 Volts present.

In L2, Power across the Resistance: Power P = Resistance R * Current I² = 2.3 Ohms (2.2 + 0.1) * 0.23164969 Amps = 0.53279 Watts, which means that a Voltage V across the Resistance R is only 1.10699 Volts, verified on the scope, but on the other side of the Inductor, there is 12,54 Volts present.

So, the huge gains seen above, across each branch L1 and L2, are not Gains across the Resistance, the load. What is going on here, why are we seeing this Gain, but not in our Load? If the input is 2.2 Watts, and Loaded Output is 1.28925 Watts + 0.53279 Watts, we only see 82% efficiency across our Resistive Loads.

Why do we see what we do? Why do we have such a large Voltage Drop across the Inductor? Between 10.818 and 11.43301 Volts...

   Chris Sykes
       hyiq.org

The Voltage drop was right, my terminology implying this Voltage Drop, or the use of the terminology in general was not what I was intending to get across. I was trying to leave an open door for the Electromagnetic Induction Process. EG: The time rate of Change of the Magnetic Field.


   Chris Sykes
       hyiq.org

[tinman]

Hey Wistiti - As always you're exactly right!!! We have not given this up at all!!!

@All - Wistiti is my friend, if anyone attacks Wistiti I am coming for you!

All I have ever asked is to be fair and honest, and that's why I will hammer any one that attacks my friends! My Friends are Fair and honest! Shared their findings freely and honestly.

   Chris Sykes
       hyiq.org

No one is attacking(or will) wistiti.
In fact,replicating his simple setup has turned out to be something worth looking into.


Brad

[tinman]

Hi Brad.

'Twas just a thought!!

Cheers Graham.

Thoughts very welcome at this point in time Grum.

Cheers

[hyiq]

No one is attacking(or will) wistiti.
In fact,replicating his simple setup has turned out to be something worth looking into.


Brad

Thank You Brad,

   Chris Sykes
       hyiq.org