Flywheel devices

[memoryman]

powering your house/business with your contraptions yet?

[MarkE]

Another classic "appeal to authority" since the going got tough, so you attempt to sidestep the "inconvenient facts" you have no way around.

Problem is you hail from there at "RG" and thanks to the world renown mark E the audience here can read what he suggested be read on fraudsters:

"www.revolution-green.com | Physics Review Board
https://physicsreviewboard.wordpress.com/category/www-revolution..."

"1. Introduction. Recently the gullible fools who operate the "Revolution-Green" website have given a wonderful helping hand to the vicious swindler and con ..."

Keep writing as ngepro, memoryman or any other name you choose and remember you still have to deal with the fact of basic physics.

Moreover; You appeal to a so-called "authority" that looks rather silly since you are part of it.

BTW: I especially enjoyed the "nit-witt" comments made by PRB ....... in light of the fact you previously wrote you were DONE.

My turn to let you know - you are DONE.

Following the link leads to this post by you:

Temporal Visitor/guest • 6 months ago

Here are the formulas used - debunk away - that part is up to you.

Users enter data in 3 different places ~ "We enter a Diameter and Thickness to define a cylindrical OBJECT."

INPUT - Diameter (inches) @ A5 ~ ("Also we now learn a radius (C5) to be used several different ways.")

INPUT - Width (inches) @ A6 ~ "From this we learn the CUBIC INCHES of VOLUME of the OBJECT made from SOLID MATTER occupies in "Space"."

INPUT - Velocity/RPM at A8 [~this is what I refer to as "design Velocity" ~]

Calculations made from inputs in INCHES:
OUTPUT - Radius is calculated in C5 ..... =A5*0.5 [~ Diameter / 2 ~]

OUTPUT - Radius is converted to metric in G5 .... radius = (d/2) * 2.54 / 100 [~ inches converted to meters ~]

OUTPUT - Radius in meters is squared in I5 .... =G5*G5 [~ Radius meters squared ~]

OUTPUT - Radians are calculated in G8 .... =A8/60*2*3.1416 [~ RPM / 60 x 2 x pie ~]

OUTPUT - Radians per second squared calculated in I8 ~ =G8 x G8 [~ Radians per second ~]

OUTPUT - Area is calculated in D5 ..... =C5*C5*3.14159265 [~ Radius x radius x pie ~]

OUTPUT - Volume C.I. is calculated in C6 .... =D5*A6 [~ Area x length (width) in inches 0.0000 ~]

OUTPUT - Mass (weight pounds) displayed in A7 .... =SUM(C6)*0.28333333 [~ Cubic inches x density lb/in^3 ~]

Pounds are weight, not mass.  The English unit for mass is the slug.

OUTPUT - Ounces are displayed in D7 .... =A7*16 [~ Pounds x 16 ~]

OUTPUT - OZ converted to kg in G7 ..... =C7/16/2.204 [~ mass = (m / 16) / 2.204 ~ ounces to kilograms ~]

OUTPUT - Surface speed I.P.S. in C8 .... =A8/60*3.1416*2*A5/2 [~ RPM / 60 x 3.1416 x 2 x radius inches ~]

OUTPUT - Inertia (kg*mA squared) in C10 .... =0.5*G7*I5 [~ Inertia = .5 * mass * (radius * radius) [* Moment of
inertia for disk type*] ~]

OUTPUT - ENERGY in JOULES in C9 .... =0.5*C10*I8 [~ 1/2 of Inertia x radians per second squared or KE = 0.5
* Inertia * (V * V) [* Kinetic energy for disk type*]

OUTPUT - ENERGY in JOULES in C12 .... =C9*2 [* Kinetic energy doubled for rim type*]

OUTPUT - Inertia (kg*mA squared) in C13 .... =C10*2 [* Inertia doubled for rim type*]

OUTPUT - JOULES converted to Torque in G9 .... =C9*0.7376 [~ Joules x 0.7376 = Torque foot pounds ~]

Torque and energy are independent properties.  You may be confusing lb. ft. and ft. lbs.  A foot pound is a unit of work described as:  One pound of force applied through one foot distance.  A pound foot is a unit of torque expressed as one pound of force applied tangentially at a distance from the pivot of one foot.

OUTPUT - DEVELOPED Horsepower per second is displayed in J9 .... =A8*G9/5252/550 [~ RPM x Torque ft.lbs.
/ 5252 / 550 ~]

HP/s are completely non-sensical units of energy per second per second.

The table below the calculator simply shows the effect of Velocity on Joules of ENERGY developed, and also displays its conversion to Torque/Horsepower

____________________________________________________

Misc. notes;
Flywheel Energy Calculator
Input US
dataform,m,d,rpm,units and convert to metric

mass = (m / 16) / 2.204 [* ounces to kilograms *]

radius = (d/2) * 2.54 / 100 [* inches to meters *]

Input Metric dataform

mass = m / 1000 [* grams to kilograms *]
radius = d/2 / 1000 [* mm to meters *]

Vsurface = (rpm/60) * 3.142 * 2 * radius

V = (rpm/60) * 2 * 3.142 [* convert RPM to radians per second *]

Inertia = .5 * mass * (radius * radius) [* Moment of inertia for disk *]

KE = 0.5 * Inertia * (V * V) [* Kinetic energy for disk *]

cforce = ( 4 * (3.142 * 3.142) * mass * radius) / ((1/(rpm/60)) * ((1/(rpm/60))))

cforce_pounds = 0.2248 * cforce

ke_disk.value = KE
ke_ring.value = KE * 2

cforce.value = cforce
cforce_kg.value = cforce *
0.1019716;
surface_speed.value =
Vsurface;
inertia_disk.value = Inertia;
inertia_ring.value = Inertia * 2;

Metric (grams, mm) ="units"
English (ounces, inches)="units"
Diameter
input name="d"

Centrifugal Force (Newtons)
="cforce"
RPM ="rpm"
Surface Speed
(M/sec)

This is a simple spreadsheet energy calculator for flywheels extracted from more complex ones I wrote for myself as a design tool to save me hours of number crunching with each and every little design change made trying to optimize systems - BEFORE wasting time and material BUILDING the wrong ones.

It computes kinetic energy values for ideal disk or ring flywheel configurations.

Most real flywheels will fall somewhere in between due to the hub and spokes. - At G14 is an "averaged" ft. lbs. (lingering from other works)

Flywheel mass and diameter can be specified in Metric (grams/millimeters) or English units (ounces/inches) with minor changes.

ENERGY Output is Metric only.

Set for US "English" input by default, simply enter diameter, width and rpm values the rest is automatic.

P.S.:
"Foot-pound" is sometimes also used as a unit of torque (see Pound-foot (torque)).

In the United States this unit is often used to specify, for example, the tightness of a bolt or the output of an
engine. Although they are dimensionally equivalent, energy (a scalar), and torque (a vector) are distinct physical
quantities.

Both energy and torque can be expressed as a product of a force vector with a displacement vector (hence
pounds and feet); energy is the scalar product of the two, and torque is the vector product.

Conversion to other units

Energy units

1 foot-pound is equivalent to:

1.3558179483314 joules

13558179.483314 ergs

0.001285067 British thermal units

0.323832 gram calories

0.000323832 kilogram calories

Power units

1 watt ≈ 44.25372896 ft·lbf/min = 0.737562149333 ft·lbf/sec

1 horsepower (mechanical) = 33,000 ft·lbf/min = 550 ft·lbf/s

Garbage In => Garbage Out

[ARMCORTEX]

I wish to thank all the participants in showing temporal your support for his work.

I will now ask you to remain on the original topic.

[Temporal Visitor]

powering your house/business with your contraptions yet?

Portions.

"Truth requires few words."

Good day

[memoryman]

"Truth requires few words." That's why your posts and website are packed with words...