Skycollection's "Pentafilar Pancake" inductively coupled "Overunity Potential".

[skycollection 1]

Yes, it is correct, I have been working with my circuit for many years with very good results, it has a COP>, <or = 1 this is possible, with this circuit I can move any type of motor that has magnets,
The advantage is that this circuit  can be connected  of all kinds of motors, as an example you can see my MAGNETIC GYROSCOPE, with three circuits and with three coils, with low power consumption, I prefer my circuit compared to John's Bedini circuit.
I myself designed this circuit in 2012 with 12 VOLTS IN, my question was how to protect my transistors with 24 volts IN, I already have the answer that is only to change the 1K resistor for a 2.2K resistor.
In a few days y will post a new video with a new generator and battery charger, in this motor i have two similar circuits connected in parallel with very low consumption of energy.

[gyulasun]

...
I myself designed this circuit in 2012 with 12 VOLTS IN, my question was how to protect my transistors with 24 volts IN, I already have the answer that is only to change the 1K resistor for a 2.2K resistor.
...

Dear Jorge,

Please allow me to note that the goal of changing the 1 k resistor to 2.2 kOhm as I suggested was to reduce any unnecessary increase in input current draw from the 24 VDC input, this resistor does not directly protect the transistors as it did not protect them at the 12 V input.  You can run your circuit with the 1 k resistor too, just check with a DC Ampermeter how the average input current draw increases and whether a higher input current draw gives any advantage in the operation of your setup. 

IF you do not use the BEMF output for anything (i.e. you leave it unloaded), then the transistors are protected only by the neon bulb which limits the collector-emitter peak voltage to 80 - 90 V, hopefully the neon bulb will not be damaged by the higher kickback spikes the 24 V input creates versus the earlier 12 V input.
I mean the neon bulb may get overloaded and may get burnt just like any light bulb which receives extra high voltage during operation.
And the moment the neon bulb fails and becomes an open circuit, the transistors will have no protection any more, and in case the kickback spikes have higher than 250 V peak amplitudes, the transistors will be toasted too.

This is why it is advisable to load the BEMF output as a precaution.  Or use two identical type neon bulbs in parallel, to reduce possible overload for a single bulb. If you can see a starting dark colouring on the inside glass wall of the neon bulb, it would be an indication of a starting overloaded operation.

Note also that the neon bulb dissipates some part of the coil kickback energy because it conducts current whenever the kickback pulse amplitude is higher than trigger voltage for the bulb, 80-90 V, this is how it protects the transistors. I mention this to realize that eventually the load for the BEMF is the neon bulb itself whenever the kickback spikes across the coil exceed 80-90 V peak values (could be seen by an oscilloscope).

Hopefully these notes are not confusing you but help better understand your circuit behaviour. 
   
Greetings,  Gyula

[skycollection 1]

Gyula, thank you very much for your valuable help, it is very important to me since I did not study electronics and this will help a lot my development in future projects.
You are really right to mention the neon bulbs, I usually see how my neon bulbs burns little by little, it turns black and after some time the transistor is damaged, (I am talking about 12 volts with a 1K resistor) now to apply 24 volts and I know that I should change the 1K resistor for a 2.2K one AND AT THE TIME PLACE RL a led bulb in the BEMF.
And thirdly, is to place two neon bulbs in parallel, I am already doing it and I am going to do several tests.
I AM USING THIS CIRCUIT ONLY TO ACTIVATE THE MOTOR, MY COILS ARE bifilar, ONE COIL GOES TO THE CIRCUIT AND THE OTHER IS PICKUP COIL, WITH A DIODE RECTIFIER AND A CAPACITOR, WITH THIS I CAN CHARGE BATTERIES.
In a few days i will post a new video, i have a new generator and i hope you can see on YOUTUBE
Thanks for your help

[skycollection 1]

SPECIAL THANKS TO GYULA, THIS IS MY NEW PROJECT, I HOPE YOU HAVE A TIME TO SEE IT

https://www.youtube.com/watch?v=kgINt2_68P8&t=48s

Saludos desde Mexico

[gyulasun]

Hi Jorge, 

Very nice job, thanks for showing the setup running.   

Will you run the setup from 15 or 24 V DC input too? No problem if you do not wish to do so of course. 

Do you happen to have a third LED bulb (120 V, 6 W, same type as the other two LEDs) ?  If you have one more, you could feed it directly from the 120 V AC mains and place it close to the other two LED bulbs to see the brightnesses of all the 3.

This way you could see whether the consumption of the two LED bulbs operated from the BACKEMF outputs approaches the nominal 6 W power the 3rd bulb is supposed to consume from the AC mains. 

Also, if you load each 66 V DC output by say a 2 kOhm resistor, then you would have two more useful loads besides the two LED bulbs and could see how the overall efficiency comes out. 

The unloaded 66 V DC outputs will drop to a lower voltage level with the 2 kOHm loads and the voltmeters would measure how many volts will be across them. Suppose for example the voltmeters will show about 20 V each, then the dissipated power in the 2 kOhm resistors would be (20V x 20V) / 2000 Ohm = 0.2 Watt each. Use 1 Watt rated resistors.

It is possible the input power to your circuits would be higher than 12 V x 0.23 A = 2.76 W when the 2 kOhm loads will be connected, you will see this.

It is also possible that the brightness of the two LED bulbs will also change (reduce a little) when the two 2 kOhm resistors are connected, you will see it.

Thanks,
Gyula