Buoyancy Generator #36

[sm0ky2]

OK, I redesigned this to make it simpler.
got rid of a few parts, and fixed some technical issues.

Pressure can be controlled by ports, that line up with a hole on the displacer mechanism.
and instead of mounting the two tanks vertically, they are side by side (gravity!! oops)
so, no valve, no latches. The location of the Buoy controls when the pressure is transferred between the two tanks.

[sm0ky2]

the next step is to select the Bouy im going to use, and performs a few tests to determine how much pressure increase is needed to compress the air-head.
I plan to use water for the first prototype, although a more dense hydraulic fluid or something might be more advantageous in future builds.

[telecom]

Hi Smoky,
I don't completely understand how your system works, but I
can understand how the system in the video works-
there the energy is supplied by squeezing the bottle, which in turn
sends more water into the dropper, and makes it to sink.
Where the energy comes from in your system?
Regards

[sm0ky2]

Hi Smoky,
I don't completely understand how your system works, but I
can understand how the system in the video works-
there the energy is supplied by squeezing the bottle, which in turn
sends more water into the dropper, and makes it to sink.
Where the energy comes from in your system?
Regards

Thanks for the interest Telecom
In this system the "initial" energy is input as pressure in tank B (the pressure ports should both be closed when the pressure is input)
Afterwards, the pressure in be released, and when equilibrium is reached, 1/2 of the pressure will be in each tank.
Coincidentally, 1/2 of this initial pressure is sufficient to compress the air in the Buoy. - like the squeeze of the bottle.
As the Buoy sinks and reaches the bottom of its' travel, the port holes line up on the displacer, and the displacer has now moved outwards
   this increases the volume of tank B, which lowers tank B's pressure by 1/2 of the initial input pressure.
Since tank A is now +1.2  and tank B is -1/2 of that amount of pressure.......
     the 1/2 pressure that entered tank A, will travel back to tank B as the pressure equalizes once again.
The Buoy will now rise back to the top, where the upper port hole lines up and the system cycles
  At this point, the displacer has traveled back into tank B, thus increasing the pressure back to there it started.

Therefore, it must be designed such that the Buoyant force is equal or greater than the force required to pressurize tank B
And the volume of the water in tank A must be greater by an amount equal to the volume displaced by the Buoy.

[sm0ky2]

little more of the "how it works"