Basic Free Energy Device

[Dbowling]

Bill,
I responded to you already. I'm sorry that the meaning of my words was not something you were able to understand.

[Hoppy]

.

[sm0ky2]

The big issue is that there is NO WAY to accurately measure the voltage being used to run the motor, since it is running between TWO POSITIVES. The closest I can come is to put that same motor connected to that same generator running the same load on a power supply and increase the voltage until the rpm's of the motor are the same as when it is running on the system. So that will ALWAYS be an approximation.

the point of reference to be measured is the two contact terminals of the motor.

from your human perspective, there is two positive poles of the batteries. but from the motors point of view, there is only the difference in voltage between the + and - terminals.
for instance, if one series batteries show you 24v, parallel ones show you 12v,
then what the motor sees is something like 24 - 12 = 12v

the current is a bit more complicated. because of the orientation of the batteries, there is less resistance in the opposite direction of the voltage potential. so the current builds up a capacitance, until it can overcome the difference in resistance, then current spikes into the batteries and they take on an amount of charge.

this will show on the scope as a change in voltage drop across the motor, though change in current may be harder to analyze because of the sample rates and the way the inductance varies over time with the reverse-bias current of the charging batteries. if your meter has a capacitor tester, you can check the capacitance of the motor circuit, that may shed some light on the mathematical side of that part of the circuit.
but even things like wire orientation can make a big difference with how the motor responds to change.

I believe you will find it harder to accurately measure or calculate the exact energy flow through that part of the circuit.
its better to take a step back and black-box the thing, measure your output to the load vs total battery capacity.
that will tell you your average I/O energy values more accurately.

once you can verify that the load consumes more than the batteries have available, without recharging them.....
then you can justify the further time and expense of taking a real look at the motor / battery interactions.

[Dbowling]

So basically you are affirming my statement that it is difficult to measure exactly how much power is consumed by the motor in this setup. A statement that was misquoted by Farmhand and then termed "rubbish".


I agree that measuring the power output of the generator IS the most accurate thing that can be measured, but that discounts the fact that there is a motor running here that is consuming power the entire time, and to say that a comparison of the power output to what is left in the batteries is what determines the worthiness of this setup completely ignores that part of the equation.


That is the same as saying that if I have a motor running off a single battery that is turning a generator I only get to count the power produced by the generator as what the system produced without taking into consideration that the motor powering the generator consumed energy that the system was responsible for producing also.


But that's ok. It will come down to the data, and people can make their own judgements. From what I have seen on the runs I have done so far, the CCA on these old batteries is slowly going up a bit and the voltage is slightly increasing over time, even though I continue to power loads. But I'm throwing all that out the window.


My proposal is this:
When I return from this trip (on the way to the airport in just a few minutes) I will begin with a brand new set of batteries. I will use SMALL batteries so that my expense is less, and it can be more easily replicated. I will do shorter runs so that the C20 rate on the batteries is not exceeded, and possibly smaller loads.
But I will record the voltage and the CCA measurement after every run. If the meter shows that the CCA on the batteries is maintained and the voltage is maintained despite the fact that I am running a motor turning a generator and running a load, that should be proof enough for anybody that there is something to this. I will keep a record of the output of the generator ONLY as the "Output" of the system. Does that sound fair enough? That SHOULD be enough to indicate that the motor is running "for free" if the system is able to maintain.


But let's be clear about something. My interest in this system is NOT and has NEVER BEEN that it outputs MORE energy than is input. My interest has been that it is able to maintain the batteries at NEAR the initial voltage despite the fact that the motor has been running the entire time. With a two coil generator connected to a stock motor pulsed with an external commutator, we had the motor running on a path of 40 watts and the generator was producing 90 watts but better than 80% of what the motor was consuming was recaptured by the "charge batteries." I have video of that. It was NOT my design, but I replicated it and verified the results. And then I built a monster unit that I am still testing. By the way, I would post that video, but it is not mine to share. And I took no video of my replication. I do, however have video of my big monster machine running and I have posted video of THAT at energetic forum on several occasions. One of those videos shows me lighting two 120 volt bulbs from a wall plug, measuring the volts and amps, then running those same two bulbs off my generator powered by the razor scooter motor producing equal voltage and amps off of one coil, then shorting out a second coil to show that when I did so, it would speed up. That was the FIRST generation of my generator, which has been rebuilt and modified a number of times since then. Unfortunately, I did NOT also show the volts and amps used to run the motor, since it was running on THIS kind of circuit and I couldn't figure out a way to show how much was being consumed by the motor. Anyway. I can post that video when I get back. No time. Leaving for airport now.

[seychelles]

HI ALL MY CONTRIBUTION THE SWITCHING CIRCUIT WITHOUT
DISCONNECTING THE BATTERY TERMINAL AND CAN BE AUTOMATIC..