Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



MEASURING DC VOLTAGE AND CURRENT USING THIS METER ?

Started by magnetman12003, April 06, 2015, 07:54:04 PM

Previous topic - Next topic

0 Members and 1 Guest are viewing this topic.

Print
Go Down Pages 1 2
User actions

magnetman12003

#5
April 07, 2015, 08:02:30 PM
Quote from: gyulasun on April 07, 2015, 06:36:54 AM
magnetman 12003 wrote:

Hi,

The first diagram shows the load in parallel with the DC voltage source to be measured. Though it looks like the load is on the positive side by the schematic drawing style but if you consider the ampermeter pins 1 and 2 as a piece of wire (due to the very low value built-in shunt resistor) then you understand the load is simply connected across the DC voltage source to be measured.

The correct question to ask is: which side of the load is the ammeter inserted, okay? This is because for a load when connected across a DC voltage source, you cannot distinguish which side it is on, it is on both the positive and the negative sides, ok? (once it is connected in parallel with the voltage source)
It is okay that your load will be a LED lamp which would have a positive and a negative connections to consider (you wrote it is a 220V DC LED).
So the answer to the correct question is: the ammeter is inserted at the negative side of the load and this is shown in Graph 1 what member Void kindly attached for you.

A suggestion: you could use a normal 9V alkali battery to feed the meter once it is able to operate from as low as 3V DC, to simplify things.  But of course the power supply is also correct to use.

Gyula
Thanks for your  explanation.  Clears things up.
Print
Go Up Pages 1 2
User actions