Increased capacitor current effect

[ayeaye]

Will in the circuit below ever be any voltage on the capacitor C2? There shouldn't be by all means, and the simulator also shows that there isn't. But if there is some anomaly in the capacitors, so that the current rises somewhat more than that necessary for charging, when the voltage on the capacitor rapidly increases, then some current should go to the capacitor C2, and its voltage should increase. It is just about finding out whether there is any, maybe unknown anomaly. Souldn't be by anything we know, but experimenting is to find out. Has anyone tried this?

There should be a small, positive voltage on C2, btw, because the diode's capacitance is in series with C2, but this capacitance is very smal,l and thus the voltage should be very small. Simulator didn't show that voltage at all. But i mean, will there be any negative voltage.

[TinselKoala]

Can you clarify the pulse source parameters? I am reading it as a pulse, from 0V to 5V, a delay of 0, with rise and fall times of 10 nanoseconds, a pulse width of 100 microseconds and a period of 1 millisecond. Is that correct?

[ayeaye]

Yes, that's correct. dc 0 is there too, i don't know why is that, but it doesn't work without it. The simulator needs some linear path to everything, or something.

[TinselKoala]

Well, I can't find any 1n4148 or 1n914 diodes in my box, so I used a 1n5817 Schottky diode instead.

Here's what I get:

The first scopeshot is with the Pulse Generator (DP-101) disconnected from the circuit to show the pulses and the channel baselines. Second shot is with pulse generator connections as the diagram indicates. The DP-101 produces a somewhat faster risetime than specified, around 6-8 nanoseconds.

(In the first shot I mistakenly had the Scopetrace Label as CAP1 but the probe is actually connected properly, to CAP2 as the photo shows.)

[ayeaye]

Thanks a lot, Tinsel.

Considering how your probe is connected, the voltage on C2 goes negative? If you have not inverted the channel.