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Overunity Machines Forum



Accurate Measurements on pulsed system's harder than you think.

Started by tinman, December 09, 2015, 07:59:10 AM

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

EMJunkie

For a NON-Uniform, NON-Symmetrical Wave, taking the Peak Value, taking 0.707 of the Peak Value and calling this the true RMS Value just doesn't seem right to me. What is it I am missing that the scope is doing that I cant see?

I mean, we are measuring the total Area from the Scope Baseline, to Scope Trace, over time.


   Chris Sykes
       hyiq.org

verpies

Quote from: poynt99 on December 13, 2015, 11:17:12 AM
It should be noted that the following (from the above post, but abbreviated and generalized):
PRx = Vrms2 / Rx
Holds for ANY wave form, with any duty cycle.
...but only when the load Rx is purely resistive.

EMJunkie

Quote from: verpies on December 13, 2015, 03:40:59 PM
...but only when the load Rx is purely resistive.



Yes, If I am not mistaken, RMS is supposed to be the DC Equivalent Figure given from a Sinusoidal Wave Form! So 0.707 of a Sinusoidal Wave would give the DC Value, of the Sinusoidal Wave Form, so the Area above the Wave, above the 0.707 would fill the missing Trace Area, giving a DC Value?

The wave Brad posted is far from Symmetrical.

See the Image below:

   Chris Sykes
       hyiq.org

verpies

Quote from: EMJunkie on December 13, 2015, 03:56:40 PM
Yes, If I am not mistaken, RMS is supposed to be the DC Equivalent Figure given from a Sinusoidal Wave Form!
Not only.
The RMS calculation can also be applied to other kinds of waveforms.

EMJunkie

Quote from: verpies on December 13, 2015, 04:31:59 PM
Not only.
The RMS calculation can also be applied to other kinds of waveforms.


Yes, yes, but only if they are symmetrical? I just used the Sinusoidal Wave Form as an example.

Is this right?

   Chris Sykes
       hyiq.org