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Overunity Machines Forum



Moon Walkers.

Started by tinman, January 22, 2016, 04:30:29 AM

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0 Members and 6 Guests are viewing this topic.

Magluvin

Quote from: tinman on January 27, 2016, 06:26:53 PM


Then after we have solved that,we can then move on to as why the lunar rovers(and every other motion) seem to be in slow motion,when our wonderful laws of physics say that this is impossible when the force of gravity is much less,and the fact that there is also no atmospheric resistance.


Due to much less gravity you would probably want to move slow, or inertia may take you farther than intended. :o ;D

Mags

Magluvin

Lol  Moon Sports!   How high could the basket be for a slam dunk on the moon? ;D

Mags

ATOM10.01

This is what MH stated

One last time, I am fully aware that the gravity is weaker and the astronaut weighs less on the moon.  The issue is that when his feet land on the surface of the moon and make an impact resulting in a certain amount of energy that is transmitted into the lunar soil, it's his mass and his velocity that count, not his weight and velocity. !

That's the correct answer and conforms a man on the moon !

Any one who thinks its all a load of rubbish needs there head opened up and a new brain installed ASAP ............... !

Only a complete idiot would now question man on the moon reality ....................................................................!

FACT .....












LibreEnergia

Quote from: tinman on January 27, 2016, 06:26:53 PM
One last time MH,if you are well  aware that his weight is less than what you stated(by over 600%),then you should also be aware that that same mass is going to have an impact that is 600% less than what you tried to present. The fact is(and you can argue all you like)that a mass that weighs 21.45kg's on the moon,is going to dissipate 600% less impact energy than a mass that weighs 130 kg's on the moon..


The impact energy is related to mass, not weight. If you can't comprehend the difference then do us a favour and learn the difference before making such ridiculous assertions.

MileHigh

QuoteOne last time MH,if you are well  aware that his weight is less than what you stated(by over 600%),then you should also be aware that that same mass is going to have an impact that is 600% less than what you tried to present. The fact is(and you can argue all you like)that a mass that weighs 21.45kg's on the moon,is going to dissipate 600% less impact energy than a mass that weighs 130 kg's on the moon,when hitting the moon surface from the same height. As we were discussing the wavering flag on the !!moon!!,then it is clear that when you quoted your weights(more than once),you were clearly trying to increase your chances at making your ridiculous claim believable by others reading this thread. Do what you tell everyone else here to do when presenting an argument of support,or data to present your theory.

The problem is that you are taking my statement and re-spinning it so that it fits inside your head and works the way you want it to work and that is not going to fly because I described the situation and not you.  I made the statement.  I never said anything at all about "hitting the moon's surface from the same height."

I will say it to you again to see if it sinks in.  I simply stated that when the astronaut hits the moon's surface it could create a tremor that makes the flag shake.  I did not talk about dropping from a certain height.  I did not even mention the final velocity.

You have to look at the situation from the way I am describing it and not the way you want to describe it.

There is no comparison taking place between Earth's gravity and the moon's gravity.

When the astronaut and his space suit hits the surface of the Earth, or if he hits the surface of the moon, the energy dissipated in the impact is a function of the mass and the final velocity, and you can ignore the strength of the gravitational field.  For sure in the moon's gravity the final velocity will be less, but that's not the point.

What's the formula for the energy in the impact?  It's energy equals one-half of the mass times the square of the velocity.

You notice that there is no gravitational acceleration in the formula for the energy in the impact.

You notice that they use mass in the formula and not weight.

Now if you can understand all that then fine.  But if you are going to go back and say, "But the astronaut and space suit are one-sixth the weight and if we drop them from the same height, bla bla bla," then you are not understanding what I am saying to you and you are only capable of taking my example and "plugging it into your brain" the only way it is going to fit.

If the only way that my example is going to fit into your head is by modifying my example and answering in the only way you are capable of answering it then you have some real limitations.  You are also failing to realize that you don't have the slightest clue if the astronaut's impact will make the flag shake or not.  It's the same thing where you fail to realize that it would be impossible from just a photograph to know if you are looking at a flag made out of nylon or cotton or rayon.  Yet you claim that you can which is ridiculous.

Ultimately this is a debate about nothing because we are not disagreeing with each other, we are simply talking about different things.  Nonetheless, if you can't agree that a statement that says, "the energy of the impact an astronaut will make on the moon's surface is a function of his mass and his velocity" is true, then you have some serious problems.