To be deleted

[nul-points]

[...]

There is no point at all in comparing input and output currents in regards to trying to analyze efficiency of the circuit.
As I have already explained, efficiency of a circuit is determined from the ratio of average output power to average input power.
Comparing currents alone gives no indication whatsoever on the efficiency of a circuit

[...]

the supply and the 2 significant current branches share a common voltage (let's call that voltage Vsupply)

the generic equation for a measure of Energy = Volts * Amps * Time

say we measure our energy for a period of 20 cycles (let's call the total time t1)

Our energy supplied for this period is

  Esupply = (Vsupply * Isupply * t1)

Our energy converted for this period is:

  Ein = (Vsupply * Iin * t1)


therefore
Efficiency, n,  = Ein / Esupply = (Vs * Iin * t1) / (Vs * Isupply * t1)

the voltages cancel (because they are common to Numerator and Denominator)


so now Efficiency, n,  = (Iin * t1) / (Isupply * t1)

the time values cancel (because they are common to Numerator and Denominator)


and now Efficiency, n,  = (Iin) / (Isupply)


this is the calculation i show in my overview diagram (and i also used in some previous posts)

so - we ARE able to calculate Efficiency using only current values WHEN the current branches share a common voltage (which they do) AND all the current readings are averaged over a common measurement period (which they are)


in my example above (overview diagram), Vsupply = 3.7V, t1 = 20 cycles (approx 60uS) - these cancel and leave us with:

  Efficiency, n, = (6.93 mA) / (5.7 mA) = 1.2  (= 120%)

[/size]
[...]

At any rate, it should be clear already that this circuit configuration gives no indication at all of OU.

lol



np

[Void]

Sigh... 

[itsu]

Come on guys, lets agree to disagree for the time being.

I need to make some 4 more measurements to get a decent average and then i can make some duration tests.
See how long it takes to drain the battery.

I can also change the frequency to see if there are major changes in the severall power users, perhaps there is a sweet spot somewhere.

_{But step  by step.}


Thanks,   itsu

[nul-points]

hi Itsu


everybody is entitled to an opinion (that includes all of the posters to this thread) - i hope that no opinions have been restricted on this thread?


maths is maths however, and if two sets of values, eg. Current and Energy (under the limits explained), are proportional then you can certainly use one set as validly as another when calculating a ratio/proportion or percentage

if i see someone claiming otherwise** as justification for denying a possibility then i am going to call it out

...and i would hope that ANY other well-intentioned and informed person would do the same


(**does anyone here think that we should not flag up maths issues like this?)



the duration tests sound good - as one part of my investigation with these tests i've been logging battery terminal voltage vs time - it''ll be interesting to compare our results and try to get a better idea of the characteristics of this circuit



np

[Void]

Come on guys, lets agree to disagree for the time being.

Hi Itsu. Anyone is free to do as they wish. It is already very clear that the circuit
is not producing OU however, and that is fair and honest assessment. All the best.