Active power from parallel resonance. Test circuit and research.

[verpies]

You say that a phase offset between the source voltage and voltage across the circuit cause an initial current draw to charge the parallel circuit

Yes

which would be exactly the same amount of current as a capacitor only circuit or inductor only circuit?

No.
The initial current drawn by a single capacitor (or single inductor) would be less than both.

What phase angle is this initial current with the source voltage?

180º

Have you seen this under test circumstance yourself?

Yes

I can't find any information on this phenomenon so would appreciate any links to help explain.

For example this link.

You can click on the SPST switch to close it. You can double click on any component to edit it.
The green scope trace represents voltage and the yellow trace represents current.
Hovering over a scope trace highlights in blue the component that the trace refers to.

[FatBird]

Where are the Output Terminals?


                                                                                          .

[verpies]

Where are the Output Terminals?                                                                                    .

To which circuit are you referring to?

[Jim36]

Hi Verpies, the only problem with the simulation is the series resistor as I was looking at 0.3 ohms due to wiring only, the dampening resistor would be in parallel and switched in on the
second half of a cycle.
Have you actually seen this happen in a physical circuit? I suppose in electronics this is something you might come across often enough. If so I think this thread has been answered and
you have saved me some time!!
Thanks for all the information you have given me.

Cheers

Jim

[Jim36]

Where are the Output Terminals?


                                                                                          .

The output terminals would be across the load as that is where I was looking to dissipate power.