Is The Earth A Flat Round Disc or Is It a Round Spherical Globe?

[gravityblock]

Here is my theory of the only way a Flat Earth is possible. hahahahaha
Yep, out of the box. (or globe I should say).
http://etherimpress.com/forum/index.php?topic=688.msg2331#msg2331

In the globe model, gravity is needed for such things as satellites, the solar system, etc.  In the flat earth model, gravity is nothing more than density.  Anything heavier than air will fall, and anything lighter than air will rise.  The properties of one model doesn't necessarily mean they apply to another model.

Gravock

[gravityblock]

Once again your post demonstrates that you are completely ignorant about astronomy. I'm not going to waste my time trying to explain to you how telescopes _actually_ work to allow very deep observations into intergalactic space. You'll just claim that my own photographs of galaxies millions of light-years away are "fake".

Hint: magnification and resolving power do not determine how far a telescope can see! 

How very clever it is for NASA to put up things on the "sky dome" that are so very dim that it takes hours of exposure time to get them to show up, right where all the star atlases says they will be, even to the merest amateur astronomer like me!

There is no other way to get a distance for the sun other than Eratosthenes' stick experiment (first image below). Just looking at it from a single point on earth will not tell you its distance, you must look at it from several points and account for the curvature or non-curvature of the distance between those points.  In his experiment, Eratosthenes assumes that the earth is a globe and that the sun is very far away in his computations for the size of the earth and the distance to the sun (~93,000,000 miles away). However, if we use his data with the assumption that the earth is flat, we come up with a different calculation for the distance of the sun, showing it to be close to the earth (~2,000 miles away).  If we move from Florida to Pennsylvania, our distance from the sun on the flat earth increases by about 30%.  The sun's distance changes according to the model of the earth we assume for the experiment.

In your following post (reply #324), you said "Yes, these distances are estimates, based on extrapolations of observations of closer objects, and the physics of electromagnetic radiation, etc.  As you can see from the above paragraph, the distance of close objects, such as the sun, depends on the correct model of the earth.  If the correct model isn't used to determine the proper distance of the closer objects, then the further objects will be wildly inflated in regards to their distance.  I hate to bust your bubble, but you're not taking photographs of galaxies millions of light years away.  You live in a fantasy world if you think otherwise!

"On March 21-22 the sun is directly overhead at the equator and appears 45 degrees above the horizon at 45 degrees north and south latitude. As the angle of sun above the earth at the equator is 90 degrees while it is 45 degrees at 45 degrees north or south latitude, it follows that the angle at the sun between the vertical from the horizon and the line from the observers at 45 degrees north and south must also be 45 degrees. The result is two right angled triangles with legs of equal length. The distance between the equator and the points at 45 degrees north or south is approximately 3,000 miles. Ergo, the sun would be an equal distance above the equator".  -- Thomas Winship, author of Zetetic Cosmogony.

Modern Mechanics describes how on a Flat Earth the sun can be computed to 3,000 miles via triangulation, whereas on a globe earth those same angles can calculate the sun to nearly 93 million miles away (second image below).

Gravock

[gravityblock]

Eratosthenes' model depends on the assumption that the earth is a globe and that the sun is far away and therefore produces parallel rays of light all over the earth.

Mainstream science has sought to explain away crepuscular rays of the sun (see first image below) that are extremely damaging to the heliocentric model, as just the result of a visual phenomenon known as linear perspective. The problem is... perspective can't explain these rays.  This video (second image below) shows that the very perspective they invoke to try and save the heliocentric model from these damaging crepuscular rays actually indicts the heliocentric model as a fraud

Gravock

[gravityblock]

You still need to explain the star-trails image I posted, taken from the Canary Islands, that shows _two_ centers of rotation, one clockwise and the other counterclockwise, at the same time. Your "rotating sky dome" model is an ignorant fantasy, nothing more, and does not fit the actual facts of observation.

What an utter facepalm bunch of ignorant garbage that video is!   

The below quote is taken from the video description as found in my previous post.

"There is no southern pole star. What folks are seeing when they look south is a perspective produced counter rotation. For example: If you are at the north pole, polaris will be directly overhead and all the stars will be rotating around it - and the stars just above the horizon will do a big circle around you staying parallel to the horizon, right?... I don't know how much you know about perspective, but notice how the clouds will angle down towards YOUR horizon THE FURTHER AWAY FROM YOU THEY ARE. Keep this in mind. The further south you go... Polaris will get lower and lower in the northern sky FROM YOUR PERSPECTIVE. Let's say you go far enough south that Polaris is on your horizon... the surrounding stars that were rotating around you at the north pole would now be rising in the east and setting in the west. And if you look to the south, you will see a counter rotation DUE TO PERPSECTIVE. This is tough to understand, I get that. Think about it for a while..."

You photographing galaxies that are millions of light years away is an ignorant fantasy based on a fairy tale as told by NASA and TPTB!

Gravock

[gravityblock]

can you stop bullshit ...

yes the earth is flat !
and you have to give a mathematic model for YOUR FLAT EARTH or  stop spamming this forum !

NASA has given us the mathematical linear model for the stationary atmosphere over a flat non-rotating Earth as mentioned in a 1988 NASA Publication.  In addition to this, the mathematics and geometry has been given to calculate the proper distance the sun is from the surface of the flat earth.  In other-words, it is you who is spamming this forum with B.S, and not me!

Gravock