Bulgarian MEG Replication

[steadyfield]

Hi steadyfield,

I think the duty cycle should be changed in a much wider range, say from 5% to 50% at least. If you cannot do this
with your present PWM generator, then just build a simple 555 timer circuit like shown here
http://overunity.com/8411/steorn-demo-live-stream-in-dublin-december-15th-10-am/msg243175/#msg243175 
The frequency and the duty cycle can be varied independently from each other.

I think somehow you would need to make sure (as a first step) that the input core should go into saturation.
To do this, remove the permanent magnet(s) from your full setup and insert a 1 Ohm (maybe 0.1 Ohm) noninductive resistor
in series with the two input coils to monitor input current by your scope. Here is a good video on this where
he changes duty cycle and first the input current of the coil increases linearly as it should, then there comes a break
and current starts increasing non-linearly: https://www.youtube.com/watch?v=oDt_Im1TtEE
He speaks Greek language, on his blog there is the schematic for his measuring setup:  http://tinyurl.com/jmrxrxs       

The goal would be to find a low duty cycle (the lower the better) setting with a given (variable) supply voltage amplitude and
input current value where the core goes well into the saturated area.
And when this is more or less achieved, and still there is no output power across the load of course, you could insert
a permanent magnet. I believe your present magnet is very, very strong. I know you tried ceramic and AlNiCo ones too
but now I suggest to monitor the input current when you insert a magnet to see how it influences input core saturation.
I think there would be a certain (unavoidable) interaction which could be minimized by using the lowest duty cycle possible
for a good input core saturation with a given input voltage level.

Do you have an air gap under or at the output coil core? And I assume your input cores are two C shapes facing each other,
without air gap, right? Or you use an E core there?

On tuning the output coil with a capacitor: probably the 100 Ohm load attenuates the LC circuit too much to see the usual voltage peak
at resonance. First try to use some kOhm load (or even no load) to easily find the resonant frequency either with changing capacitors
and / or sweeping the input frequency.
No need to place a capacitor in parallel with the input coil.

I suggest reading member Getca posts in his findings, he reported COP>1 result.
http://overunity.com/4300/a-truly-overunity-transformer-meg/msg134162/#msg134162 

I attached a video, taken from youtube long time ago, that nicely show how permanent magnets can passively cause local core saturation
to create a virtual "air gap" in the core. Unfortunately I cannot remember who uploaded it to give credit to him.

In your video ( https://www.youtube.com/watch?v=Iz4POclJ8ws ) there is still output power when your permanent magnet is horizontally attached
to the side of the lower ferrite bar  and power disappears only when you completely remove that magnet.  This may indicate it is a
very strong magnet for the job? Or too small air gap at the output coil side in the core?  There exists a strong magnetic coupling between
the input core and the output core in your setup
As another test, you may wish to swap the places of the permanet magnet and the input core as per the animated gif file shows in Getca post.

Regards,
Gyula

Hi, Gyula

Firstly I would clarify my setup a little bit. The cores of the input coils are two "C" ferrite core.  I'm not using a single-ended driver. The H-Bridge is used to drive the input coils. The voltage applied to the input coils is a bipolar square wave [-Vdc,+Vdc]. When the dutycycle is 50%, the net volt-second applied to the input coils is zero and the input current is less than 10mA (The bench power supply displays 0.00A). And there is no output. 

When the input square wave breaks symmetry (either greater or less than 50%), the input current rises.  The more the dutycycle deviate from 50%, the more the input current. When the dutycycle starts to deviate from 50%, the input current increases and the output also increases. When reached a dutycycle of 52.5% (or 47.5%), the output amplitude is the highest. As the dutycycle continues to deviate, the output amplitude begins to fall while the input current continues to rise. So as for the current setup, the 52.5% or 47.5% might be the "sweet spot".

I have tried adding and varying the air gap of the output. The larger the air gap, the less the input and output. So the coupling is still here.

I will try attaching a current sensing resistor in series with the input coils to see if there is saturation, and I will also remove the loads in parallel with the capacitor to better find resonance. Do you think I should use a single-ended driver instead of a H-bridge?

Regards,
Steadyfield

[gyulasun]

...
I will try attaching a current sensing resistor in series with the input coils to see if there is saturation, and I will also remove the loads in parallel with the capacitor to better find resonance. Do you think I should use a single-ended driver instead of a H-bridge?
...

Hi Steadyfield,

Thanks for the further clarification on your setup. Sorry but I have not considered driving this MEG with a H-bridge.
I may be wrong but it looks like the H-bridge insures eventually the equivalent of a single ended drive
which feeds the coils with 2.5% duty cycle pulses when you change the 50% duty cycle a little.  Is this correct?
If yes, then no need to drive the coils with a single ended driver, unless you wish to check it too.

My understanding is (though I may be wrong) that your so called bipolar square wave with its near 50% duty cycle
is not an ideal waveform here because there is no current change during its 'flat' horizontal top and bottom portions.
And in case you disturb this waveform symmetry, it is the difference which lets the current flow and the 2.5% difference
seems optimal for your setup. I do not mean such drive is wrong, just different from the others.
IF we consider the inventor's half wave drive
(see here http://overunity.com/4300/a-truly-overunity-transformer-meg/msg134662/#msg134662 ), then it is sure the
peak current (to cause saturation) occurs when the half wave voltage is at its peaks value, so the "ON time" of the flux switch
is in the peak voltage range.
It is possible that with a single ended drive and with say 2-5% duty cycle range you would receive the same output you got so far.
Sorry that I have no hands on tests on the Bulgarian MEG, years ago I built the MEG setup by Thomas Bearden et al
but got only 87% efficiency. Of course I realised that the Bearden MEG setup shown in the patent is a mere pulsed transformer.

Gyula

[lancaIV]

One of the last international entries,also listened as www.patentauction.com offer :


https://worldwide.espacenet.com/publicationDetails/biblio?CC=ES&NR=1143608Y&KC=Y&FT=D


Este generador no precisa de movimiento o rotación de sus elementos y no genera residuos contaminantes de forma directa.
~ static dynamo by Keiichiro Asaoka


pulsed DC or AC : anti-/matter sphere generator/transformer


and staying attended: http://www.energymev.org