re: energy producing experiments

[magneat]

Delburt Phend, your question was for me?
English is not my native language, so I might not understand you correctly.
I don't understand the expression "despin concept".
it would be more clear if there was a drawing + formulas.
my point of erosion is outlined in the following posts (if you have not read them):
https://overunity.com/17113/re-energy-producing-experiments/msg541516/#msg541516


Obert effect video - https://www.youtube.com/watch?v=dq5jbPoE_Cc
popular explanation of the Obert effect - http://hopsblog-hop.blogspot.com/2013/10/what-about-mr-oberth.html


mathematical presentation of the Obert effect, and assumptions about its presence in OU generators:
https://overunity.com/17113/re-energy-producing-experiments/msg541532/#msg541532
https://overunity.com/17113/re-energy-producing-experiments/msg541788/#msg541788
https://overunity.com/17113/re-energy-producing-experiments/msg541808/#msg541808
https://overunity.com/17113/re-energy-producing-experiments/150/

[Delburt Phend]

https://www.youtube.com/watch?v=boLk57cKNao

Please notice that the spheres swing out from the cylinder and the cylinder stops.

The cylinder's mass is a great deal larger than the spheres.

The spheres absorb all the motion of the cylinder. This is the despin effect.

Also note that the rotational motion of the cylinder is restarted. This restart guarantees that this motion transfer is momentum conservation.  Because as proven by ballistic pendulums energy is not conserved when a smaller mass transfers its motion to a larger mass. And a great deal of motion would be lost.

The spheres could be released as the cylinder is stopped and they could be directed upward.

The increase in energy is proportional to the mass difference. If the total (cylinder's and spheres') mass is ten time that of the spheres then the energy increase is ten times; when the spheres have all the motion.

For other experiments type delburt phend youtube into the search engine. 

[magneat]

...For other experiments type delburt phend youtube into the search engine.

Your experiments are very interesting!
but, how do you see their practical application for obtaining OU? Do you already have thoughts on this?

[sm0ky2]

How does that compare to when the cylinder is on a bearing?


Tetherball?
Bolas?

[Delburt Phend]

Absolutely

The one gentleman had a wheel that must have had a mass of one hundred kilograms. And it was probably moving several meters per second; so lets start there. With 100 kilograms moving 2 meters per second. And let transfer that momentum to 5 kilograms.

One hundred kilograms moving two meters per sec is 200 units of momentum.

When we transfer all of the momentum to 5 kilograms the five kilograms will have to be moving 40 meters per second. At 40 meters per second it can rise 81.5 meters.       d = 1/2v²/a

After it has risen 81.5 meters we can place it on a stack of eighty 5 kilogram masses 80 meters high.  These masses would be spaced 1 meter apart.

You can drop the entire stack one meter. And all you have to do to return the stack to its original configuration is to take the lowest 5 kilograms and throw it back to the top.

You can throw the lowest five kilograms back to the top by accelerating the 100 kilogram rim to 2 meters per second and transfer the momentum into a five kilogram mass.

A stack of 80 five kilogram masses has a mass of 400 kilograms. 400 kilograms can accelerate a 100 kilogram rim to 2 m/sec after the stack has dropped a distance of .2548 meters. But in this drop of one fourth meter not only is the rim moving 2 m/sec but so is the 400 kilograms stack.  So now you have 1000 units of momentum and you only need 200 (5 kg * 40 m/sec) units to reload the stack.

200 units of momentum is one fifth of 1000 and the distance dropped is only a fourth of a meter. The stack was dropped one meter.   One fifth of the momentum and one fourth of the distance is only 5%.

The stack is reconfigured by using only 5% of the motion produced from the one meter drop of the stack.