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Overunity Machines Forum



re: energy producing experiments

Started by Delburt Phend, February 04, 2017, 09:31:19 AM

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Delburt Phend

By changing the dimensions of this experiment we can get a doable measurable experiment. One hundred meters is too high for an amateur to measure but 10 meters is not. You can tell the difference between 30 feet and 60 feet. I have already throw to the top of our trees, which is 80 to 90 feet.

So lets rearrange the above experiment to throw 10 meters upwards. This is also the height of the stack of drive masses.

And lets let the drive distance drop be .0667 meters. Lets place one kilogram in this drive distance of .0667 meters. One meter can be divided by .0667, which shows that 15 one kilogram masses can be evenly spaced along the distance of one meter.

There are 10 meters for such 15 mass units so the drive mass is 150 kilograms.

The rotational inertia of the wheel should be about 19 times (19 * 150 kg = 2850 kg) this is so that the total mass accelerated is 20 times the quantity of the drive mass. This 20 to one will give us an acceleration of .4905 m/sec².    9.81 m/sec² / 20 = .4905 m/sec²

So the speed (at the shaft) after the drive mass has dropped .0667 meters is going to be about .2557 meter/sec.  The square root of (.0667 m * 2 * .4905 m/sec²) = .2557 m/sec.

Now this is 3000 kilogram moving .2557 m/sec which is 767.1 units of momentum.

One kilogram moving 14.007 will rise 10 meters. This is 14.007 units of momentum. One kilogram rising ten meter will restore the configuration of the stack; which has dropped .0667 meters.

So the system can reconfigure with 14.007 units of momentum and it produces 767.1 units.

Now we need to apply the radius to mass rule for the rotational inertia of spinning objects. If the accelerated mass (3000 kg) is at ten times the radius of the shaft then the wheel only needs to have a mass of 300 kilograms. But this 300 kg is moving 2.557 m/sec. For the same 767.1 units of momentum.

The thrown mass is 1 kilogram: which has come off the bottom of the 10 meter stack.

So: as in the cylinder and spheres experiment we attach two ½ kilograms masses to the outside of the wheel. We spin the wheel and release the spheres on their tethers and one of them will rise up to the tree tops. And the other sphere will thump into the ground; I have done it many times.

But not with a 300 kilogram rim mass wheel. So lets start downsizing.

I use 152 gram one inch spheres. Two of these are 304 grams instead of  the 1000 grams in the above experiment. This means that the 300 kilograms for the one kilogram above becomes 91.2 kg for the .304 grams of thrown mass.      .304 * 300 kg = 91.2 kg.

Using a thrown mass of .304 kg give a drive mass of .304 kg * 150 = 45.6 kilograms. And an accelerated mass of 912 kg and a momentum of 912 kg * .2557 m/sec = 233.19 units.

This means that I can walk into the yard and spin a 91.2 kilogram rim up to 2.557 m/sec and see if one .152 kg mass can rise 10 meters up.

Well maybe some of you are 91 kilogram hombres; but I am more like a 3 kilogram guy. But if I use a 3 kilogram wheel does that mean that I can spin it 30 times faster? 91.2 kilograms moving 2.557 m/sec is 233.1 units of momentum. And 3 kilograms moving 76.71 m/sec is also 233.1 units of momentum.

So this means I can take a 3 kilogram rim that has two 152 grams masses attached, in the cylinder and spheres fashion, and I can spin it as fast as I can. And after I release the spheres when one of them reaches the tops of the trees then it proves that the .0667 meter drop can be repeated. The spheres have more energy (½ * 1 kg * 14.007 m/sec * 14.007 m/sec  + Extra meters) than  (½ * 3000 kg *.2557 m/sec .2557 m/sec) when they rise higher than 10 meters.

Did you notice that the 3 kilogram wheel already has a velocity of over 5 times faster than the spheres would need to rise 10 meters?

Okay lets check some of the relationships to see if I am staying consistent.

The stack of one kilogram masses has 767.1 units of momentum for the one thrown kilogram to work with; and a thrown mass of .304 kg has 233; checks

The one kilogram needs 14.007 units of momentum to cycle and the .304 kg needs 4.26

300 kilogram moving 2.557 m/sec has 767.1 units of momentum: and  3 kilograms moving 77.6 m/sec has 233 units   14.007 / 767.1 and 4.26 / 233 is only  2% to cycle.

Baseballs have a mass of 142 grams and they make great tree ornaments. 

Delburt Phend

The difference between Newtonian momentum and energy is that momentum is Force times time: and energy is force times distance. And the original definition of energy was Liebniz's mv².

So the energy of motion is  Fd = mv²      and      F = ma is Newtonian momentum.

Acceleration is v / t.    So F = ma   is   Ft = mv

Distance  is v * t      So Fd = mv²   is    F * v * t  =  m * v * v  We can simplify the equation by dividing both sides by v.   And we get Ft =  mv   which is Newton's equation.    So it appears that kinetic energy is a mathematical error: which would explain why it can not be conserved in the lab.  Because the correct equation had been multiplied by v.

More importantly the energy of motion needs imaginary heat to be conserved; as in a ballistic pendulum. Distance is merely a consequence of acceleration; and kinetic energy is not a conserved quantity.

I thought I would discuss Newtonian Mechanics in a manner that would be useful. And at the same time discuss the alternate concept that replaced it.

When an object is dropped it gains a speed of 9.81 m/sec in the first second. The object travels 4.905 meters because its average speed is (the starting speed) + (the final speed) / 2 = 4.905 m/sec. This average velocity is applied for 1 second. For a one kilogram mass this is 9.81 units of momentum.

When this same object continues to drop the second second it will travel 14.715 meters in that second.  This is because its original speed is 9.81 meters per second and the final speed is 19.62 meters per second for an average speed of (9.81 + 19.62) / 2 = 14.715 meters traveled in one second. For a one kilogram mass this produces 9.81 units of momentum; because the speed has increased by 9.81 m/sec.

When this same object continues to drop the third second it will travel 24.525 meters in that second.  This is because its original speed is 19.62 meters per second and the final speed is 29.43 meters per second for an average speed of (19.62 + 29.43) / 2 = 24.525 meters per second; and it traveled for one second. For a one kilogram mass this produces 9.81 units of momentum; because the speed has increased by 9.81 m/sec.

When this same object continues to drop for the twentieth second it will travel 191.295 meters in that second.  This is because its original speed is 186.39 meters per second and the final speed is 196.2 meters per second for an average speed of (186.39 + 196.2) / 2 = 191.295 meters per second; and it traveled for one second. For a one kilogram mass this produces 9.81 units of momentum; because the speed has increased by 9.81 m/sec.

So Newtonian Mechanics produces 9.81 units of momentum for each and every second that the one kilograms mass drops.

What replaced Newtonian Mechanical is the Law of Conservation of Energy that says the first second produces 48.11 joules of energy: and the second second produces 144.35 joules: the third 240.59 joules and the twentieth 1876.6 joules.

When you use a 1 kilogram drive mass in a 10 kilograms Atwood's one second produces 4.811 joules of energy and 9.81 units of momentum.

A 1 kilogram drive mass in a 100 kilogram Atwood's produces 9.81 units of momentum and .4811 joules of energy in one second. 

Force applied for one second always produces a uniform quantity of momentum; and the production is independent of  how fast the accelerated mass is moving. And momentum is conserved in collisions.

Force times distance on the other hand produces an infinite number of energies. As an example one kilogram dropped for one second can produce: .4811 joules, 4.811 J, 48.11 J, 144.35 J, 240.59 J, 1,876.6 joules. Yet when interacting in a collision most of this energy is lost. Kinetic energy is not conserved by a ballistic pendulum because multiplying by an extra v give massive amounts of energy that can not be found.

lltfdaniel1

A yo-yo uses gyroscope techniques as you know.


Rotation of the Earth is a quite involved process. Deep knowledge of certain areas of physics is indispensable for its understanding and researching. It is necessary to clarify the physics of rigid bodies' rotation because the usage of terms precession and nutation by experts in geosciences are generally not correct, sometimes confused. In physics nutation is the motion of a free gyroscope, and precession is the motion of a heavy one. The torque of an external force causes the precession of a heavy gyroscope, but nutation is a motion of a free gyroscope, if its rotation has not started around its symmetry axis. While the cause of precession of a rotating body always arises from the effect of external mass sources, nutation is exclusively a function of the intrinsic mass distribution of the rotating body. After discussing some important aspects of rotational mechanics (motion of a free and a heavy gyroscope), the Earth's nutation and certain elements of Earth's precession (normal precession, lunisolar precession, planetary precession, disturbing precession) are defined and discussed. A new terminology is proposed, e.g. disturbing precession instead of the widely spread deceptive expression of astronomical nutation.


Read more here > https://www.researchgate.net/figure/Precesional-motion-of-the-Earths-rotation-axis-lunisolar-precession_fig4_250008115 and https://www.researchgate.net/publication/250008115_Physical_backgrounds_of_Earth's_rotation_revision_of_the_terminology/download from that website.

Regarding the gyroscope technique and newton, what stays in motion actually stays in motion, exactly the same with the torque output.

The free energy secret is in toys whey and i bought one for fun, https://www.amazon.co.uk/gp/product/B007FF5PVC/ref=ppx_yo_dt_b_asin_title_o01_s00?ie=UTF8&psc=1

The gyro scope technique is the secret sole key for some free energy inventions so click and read this and come to your own conclusion > https://drmyronevans.files.wordpress.com/2016/12/iufooutlinev23.pdf
68:16 But by this, THEIR KNOWLEDGE (science - 1 Tim. 5:20), THEY PERISH, and by this also its power consumes them.

twh 1:1 Thousands of earth years ago,far away,in this galaxy,on the morning star(venus),the Lord Guardian Of Divinity,King ruler and Guardian of the Universe,put down a revolution led by Lucifer(Iblis)

Delburt Phend

More about the discussion on the 12th.

If a one kilogram mass accelerates another 99 kilograms (as in an Atwood's machine) for 20 seconds it will be traveling only 1.962 m/sec. It will have dropped 19.62 meters and the 100 kg system will have 192.47 joules of energy.

If a one kilogram mass accelerates itself in free fall (in a vacuum) for 20 second it will be traveling 196.2 meters per second. It will have fallen 1962 meters and it will have lost gravitational potential energy of 19247.2 joules. If we direct the one kilogram moving 196.2 m/sec upward it will 'ideally' travel back up 1962 meters; and its gravitational potential energy will be restored.  But its kinetic energy (19247.2 J) is a math error and it is not there. Restoration of height is a natural consequence of velocity.

The true motion energy for one kilogram moving 196.2 m/sec can be found by collision with a 99 kilogram mass at rest. The combined mass of 100 kilograms will be moving 1.962 m/sec and will have 192.47 joules of energy.

The kinetic energy is not there: it doesn't disappear as heat (as in a ballistic pendulum) it was simply never there. The kinetic energy scheme was invented to prevent people from seeing how easy it is to make energy.

lltfdaniel1

Quote from: Delburt Phend on March 14, 2020, 09:44:47 PM
More about the discussion on the 12th.

If a one kilogram mass accelerates another 99 kilograms (as in an Atwood's machine) for 20 seconds it will be traveling only 1.962 m/sec. It will have dropped 19.62 meters and the 100 kg system will have 192.47 joules of energy.

If a one kilogram mass accelerates itself in free fall (in a vacuum) for 20 second it will be traveling 196.2 meters per second. It will have fallen 1962 meters and it will have lost gravitational potential energy of 19247.2 joules. If we direct the one kilogram moving 196.2 m/sec upward it will 'ideally' travel back up 1962 meters; and its gravitational potential energy will be restored.  But its kinetic energy (19247.2 J) is a math error and it is not there. Restoration of height is a natural consequence of velocity.

The true motion energy for one kilogram moving 196.2 m/sec can be found by collision with a 99 kilogram mass at rest. The combined mass of 100 kilograms will be moving 1.962 m/sec and will have 192.47 joules of energy.

The kinetic energy is not there: it doesn't disappear as heat (as in a ballistic pendulum) it was simply never there. The kinetic energy scheme was invented to prevent people from seeing how easy it is to make energy.


I agree 100% about the kinetic energy scheme that was invented and the way the earth processes work would shatter that concept, but science it self rejects this explanation sadly, if you applied all the known laws of energy to it, it won't answer as to why it works or make sense in that regard but not all of it though, there are some independent more open minded scientists to accept the truth about it.

This torque output effect is better explained using Russian torsion theory regarding what your pondering about and the gyro effect.

Here is something about torsion theory > https://blog.world-mysteries.com/science/torsion-the-key-to-theory-of-everything/

So view torsion as the magic key which is what your after, the torque manifests as a torsion wave with regards as to what your playing or working out with here.

Also read > https://infinityexplorers.com/teslas-torsion-fieldswaves-bosnian-pyramids

https://infinityexplorers.com/everything-light-incredible-interview-nikola-tesla-1899

It is also crucial to work out the torque pendulum, here is some demonstration  > https://www.youtube.com/watch?v=GcPO2pKaiO0

To keep the torque pendulum running you will need an input (maybe electric motor or whatever) taking advantage of this to keep the whole process going and maintained perhaps instead of manually doing it.

It would have an effect of little power input to bigger output power perhaps with the way this effect works

It would have to be maintained using forced precession methods i would not be surprised if you get more out than in but take that with pinch of salt
68:16 But by this, THEIR KNOWLEDGE (science - 1 Tim. 5:20), THEY PERISH, and by this also its power consumes them.

twh 1:1 Thousands of earth years ago,far away,in this galaxy,on the morning star(venus),the Lord Guardian Of Divinity,King ruler and Guardian of the Universe,put down a revolution led by Lucifer(Iblis)