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Overunity Machines Forum



re: energy producing experiments

Started by Delburt Phend, February 04, 2017, 09:31:19 AM

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0 Members and 6 Guests are viewing this topic.

lancaIV

Quote from: lancaIV on January 13, 2021, 12:30:37 PM
Hello,related #211 I reed yesterday in old threads in a discussion between Gustav Pese and Kator01 as given example by Kator/Mich(a)el a similar physical configuration !
Probably he,Kator01, can give good advices/links/help !

Sincere
OCWL
I refound it : https://overunity.com/30/extra-electric-power-power-amp/45/    #54 and meaning that translated does more sense  ::) :
A DESIGN FOR A PERFECT QUANTUM RESONANT PENDULUM

http://www.unifiedtheory.org.uk/

Here the principle of storing and retrieving centrifugal force is explained very well. Nobody had such an idea so far. However, it must be built differently than shown. Centrifugal forces, which are actually inertial forces (from the point of view of a co-rotating observer) take on enormous dimensions.

Here, too, the solution lies in moving away from the "rigid" concept towards a dynamic one so that the enormous potential can be decoupled.

Example: A weight of 100 grams generates a centrifugal force of approx. 1480 N [kg m / sec exp ^ 2) when rotated 20 cm from the axis at 3000 rpm.

First you have to temporarily store this force, if you let it run against a resistance for 1 second, for example (= impulse braking, the weight remains on the axis, it does not fly away tangentially) you get an impulse = F xt = force times time of 1480 kg meter / sec.
If you let go of the weight (as every hammer thrower does), you get the impulse = F xt = M x V (mass times speed) = 0.1 kg times 47.12 meters / sec = 4.7 kg m / sec, i.e. only approx. 1/300 of the possible centrifugal force impulse (in SI units)

What a difference if done right.
So far, nobody has thought of it because all circular systems are viewed rigidly.
The author claims that he took a DC motor with a similar configuration to 3000 rpm, then switched off the DC input, after which the motor continued to run with a vibrating noise for 20 minutes (auto-resonance) before it switched off then had to brake violently.

lancaIV

Quote from: helmut on January 15, 2021, 05:02:14 AM
Gustav Pese ... he should Rest in peace... he would love to see what Mr Zündel developed  regardimg  to gravity. Hello Mr de Lanca .. long time.
??? Wer sind Sie ?  ???
;D Halloechen,helmut und Duisburg !? Oder Wohnort geaendert ? Immer noch politisch links von der Mitte ?  ::)

                              Oder nun doch "eingefleischter"  Merkelianer ? ;) ( An Sitzfleisch mangelt es dieser Person ja nicht ! :-\ )

                              Die oide "Ueber-Mutti der Nay-ssion" geht ja baldigst von Bord ! :'( Neuer bloeder Lotse gesucht !

                             Sie vielleicht ? 8) Erst Duisburg unter Sparkommissariat dann die ganze Nay-ssion ! Lock-out forever ! :o ;D


      Bei overunity.de war doch ein Frankfurter/Main( der mit dem Kaefer,nicht zwei-beinig,vier-raedrig) mit dem "Ei"      (Wasserstoff/bzw.HHO-Kata-/Elektro-lyse)
      anderes "Ei" https://www.weka.de/einkauf-logistik/das-wasserstoff-ei-des-kolumbus-revolution-in-der-energieversorgung/
      https://www.youtube.com/watch?v=kfYiQVzB3Cg

      individuelle pro/contra Meinung https://www.youtube.com/watch?v=PkbjkXTBsyw

Schon wieder Freitag , also schoenes geruhsames -home office - Wochenende wuenschend !

Bis dann mal
OCWL

p.s.: habe den Research nicht verlassen ,aber guenstige Technologie-Alternativen zu Imris/Ferreira Spulen
da spielt ein hiesiger Ex-Phillips-Ingenieur, aktuell als Professor taetig, eine Rolle,wobei wir " uns technologisch" gegenseitig befruchten

helmut

Hallo Hallo . Ja , wir kennen einander. Der Käfer aus Frankfurt rollt wohl nicht mehr. Leider hat der Schöpfer sich zurück gezogen. Andere werkeln nun weiter an HHO und meine eigenen Aktivitäten mit OLGA der Trennzelle ruhen noch eine Weile.  300 Tage bis zur Rente. Zwischenzeitlich hatte ich einen Abstecher in die Electromedizin getan und stecke noch fest , bis ich mir genug Wissen über die Frequenzerzeugung im Ghz Bereich angeeignet habe. Aus Duisburg komme ich erst raus , wenn ich die Hütte verkauft habe. Mutti und ihre Schergen giften uns mit ihrer hässlichen Fratze an. Oft denke ich über Auswandern nach. Ich grüsse Sie.


Delburt Phend

You could construct a strong light wheel made of modern fiber that had a high quality center bearing. The wheel could be attached by a string to a 399 kilogram mass floating on dry ice. This same wheel could have a second string attached that had a 1 kg mass on the end.

The string for the one kilogram is arranged so that is can wrap around the wheel and the 399 kg is just pulled by the wrapping of the one kilogram.

What proponent of COAM are saying is that the one kilogram that is only moving twenty meters per second can wrap around the wheel and cause the 399 kilograms to achieve a velocity of 1 m/sec. The one kilogram only needs a string long enough to give the one kilogram a angular momentum sufficient for the 400 kg * 1 m/sec movement. This is ridiculous 20 units of momentum can not make 400 kg*m/sec.

Delburt Phend

This is about an Atwood's machine with 199.5 kg on one side and 200.5 on the other.

Yes; the difference between M1 and M2 is 1 kg; and the sum is 400 kg. That means that the acceleration 'a' is 1/400 times 9.81 m/sec/sec.  a = .024525 m/sec²

Now the formula for time is used; d = ½ at²   With a drop distance of one meter and an acceleration of .024525 m/sec² we have a drop time of 9.03 seconds.

Doing the same for free fall we get a drop time of .4515 seconds.

9.03 sec / .4515 sec = 20

The force of 9.81 N is applied for 20 times as long in the (400 kg to 1 kg) Atwood's machine.

The final velocity of the Atwood's is found by this formula;  d = ½ v²/a;   this is just d = ½ at²  where v/a is substituted for t.

The final velocity for one meter of free fall is 4.429 m/sec; The final velocity for the 400 to one Atwood's is .22147 m/sec.

This is 4.429 (1 kg * 4.429 m/sec) units of momentum for free fall and (400 kg * .22147 m/sec) 88.589 units of momentum for the Atwood's. This is 20 times as much momentum produced; and 20 times as much time over which the force acts.

It takes 4.429 units of momentum to return the one kilogram of imbalance to the original position of the Atwood's.  And you get 88.589 out.

Now this is the quantity of momentum that Newton said was conserved and you put 4.429 units in and you get 88.589 units out. Every cycle; 4.429 in 88.589 out.

All that is needed is to transfer the motion of the 400 kilograms into the one kilogram: and that can be done with a cylinder and spheres machine.

There is also a modified Atwood's that eliminate the up and down motion; if that bother some.