Witness the Free Energy effect

[blueplanet]

Shedding light reveals you should learn basic electronics 101 before making such statements. First, B2 is not 0.9KV. It's about 10mV (0.01 volts). Second, power is not peak anything. It's rms. Third, you need to know phase angle to do power calculations. Fourth, LTspice will tell the power at B2, which is 11.5mW (0.0115 watts). Fifth, you have no clue how much power you'll get at the surface. Why are you here? You're accomplishing nothing. When I want to release this technology to the world I will do so and it will not be here at this website. Now what?

If the power of the air space is 11.5mW, then the voltage is about 11.5mW/2A=5.25mV. By the calculation, the characteristic impedance is roughly 5.25mV/2A = 0.0029 ohm.  This impedance means the current is mainly magnetic and the electric field strength of the air space is almost zero. This impedance does not appear to be the characteristic impedance of air at 16MHz, which should be around 377 Ohm.


According to one of your diagram posted here, the air space is apparently the spacing between two concentric coils. I might be wrong.  If the dielectric is truly air, only plasma can generate this  kind of impedance.[/size]

[/size]
You are right. I have no clue how much power we can harvested from the surface simply because the surface impedance of the air/ground has not been specified. Like other forum members, I am trying to learn from you. If you think we are not ready to learn from you, then it is also okay. Perhaps, you can publish your idea in a high impact journal.  [/size]

[/size]
As I said, I hope you can shed more light on this topic.[/size]

[/size]

[Theoretical Research]

If the power of the air space is 11.5mW, then the voltage is about 11.5mW/2A=5.25mV. By the calculation, the characteristic impedance is roughly 5.25mV/2A = 0.0029 ohm.  This impedance means the current is mainly magnetic and the electric field strength of the air space is almost zero. This impedance does not appear to be the characteristic impedance of air at 16MHz, which should be around 377 Ohm.


According to one of your diagram posted here, the air space is apparently the spacing between two concentric coils. I might be wrong.  If the dielectric is truly air, only plasma can generate this  kind of impedance.[/size]

[/size]
You are right. I have no clue how much power we can harvested from the surface simply because the surface impedance of the air/ground has not been specified. Like other forum members, I am trying to learn from you. If you think we are not ready to learn from you, then it is also okay. Perhaps, you can publish your idea in a high impact journal.  [/size]

[/size]
As I said, I hope you can shed more light on this topic.[/size]

[/size]

Why not take my advice about taking some EE classes or learning on your own or from a tutor before making such statements here? That's a serious question for you.

Again, power is not peak. It's rms. Convert to rms by dividing peak by sqrt(2). IMO any academic scientists should know that. Furthermore you need to know the phase angle difference between voltage and current. You can do that manually in LTspice or let LTspice do it for you.

The classical impedance of space has nothing to do with the impedance of the core. Reactance of displacement current varies with frequency and has absolutely nothing to do with the fixed 377 ohms. The 377 ohm is the characteristic impedance of free space. It's an expression of the relationship between the electric-field and magnetic-field intensities in an electromagnetic field propagating through a vacuum. Do you know the difference between near & far fields?

[blueplanet]

Why not take my advice about taking some EE classes or learning on your own or from a tutor before making such statements here? That's a serious question for you.

Again, power is not peak. It's rms. Convert to rms by dividing peak by sqrt(2). IMO any academic scientists should know that. Furthermore you need to know the phase angle difference between voltage and current. You can do that manually in LTspice or let LTspice do it for you.

I just need a quick estimation on the order of magnitudes for different parameters.

The classical impedance of space has nothing to do with the impedance of the core. Reactance of displacement current varies with frequency and has absolutely nothing to do with the fixed 377 ohms. The 377 ohm is the characteristic impedance of free space. It's an expression of the relationship between the electric-field and magnetic-field intensities in an electromagnetic field propagating through a vacuum. Do you know the difference between near & far fields?

Whatever you like...


By the way, in an attempt to understand your vortex detector better,  I have tried to include B2 and exclude B2 in your LTspice schematic. In both cases, your vortex detector gave exactly the same simulated output. This B2 is apparently not relevant.


There are two identical inputs for the mixer of your second version of the vortex detector. The main ingredient of these two inputs is apparently the output signal of the oscillator. I have no idea what you are you trying to detect.

[Theoretical Research]

I just need a quick estimation on the order of magnitudes for different parameters.


Whatever you like...


By the way, in an attempt to understand your vortex detector better,  I have tried to include B2 and exclude B2 in your LTspice schematic. In both cases, your vortex detector gave exactly the same simulated output. This B2 is apparently not relevant.


There are two identical inputs for the mixer of your second version of the vortex detector. The main ingredient of these two inputs is apparently the output signal of the oscillator. I have no idea what you are you trying to detect.

Well, multiplying the AC peak or rms voltage on a capacitor by its current to calculate power is not called an estimation. It's called an error. It's 100% fact you do not know how to properly calculate power in an AC circuit, and don't understand why you need to know phase angle. Basic concepts people learn in electronics 101. The worse part is that after all these posts you've refused to admit your simple errors.

Sorry, but I don't have time to teach you about electronic mixers.

Didn't I say I wasn't going to bother with this? This is the last time I'm replying to you. Go ahead and do your stuff lol. smh

[blueplanet]

Never mind.


I have requested for a red pill. I have not cancelled my request yet. I am not the only one requesting this red pill.


I hope that your red pills will be available by 2020. Do not forget to send these to us in DHS or Fedex.  Don't send us through USPS.


Hopefully, by 2020, your upcoming free energy secret can save the whole world from the attack by the terrorists and the North Korean.

Well, multiplying the AC peak or rms voltage on a capacitor by its current to calculate power is not called an estimation. It's called an error. It's 100% fact you do not know how to properly calculate power in an AC circuit, and don't understand why you need to know phase angle. Basic concepts people learn in electronics 101. The worse part is that after all these posts you've refused to admit your simple errors.

Sorry, but I don't have time to teach you about electronic mixers.

Didn't I say I wasn't going to bother with this? This is the last time I'm replying to you. Go ahead and do your stuff lol. smh