Dr Ronald Stiffler SEC technology

[TinselKoala]

@gyula, slider:
Yes, the Rigol scope puts out a 3v (approx) max p-p voltage from the probe compensator output. The probe 1x-10x switch or the channel attenuation setting is not correct in Slider's scopeshot above.

[Slider2732]

Gyula - Many thanks for the tips.
Will try the 9V battery and look into the exact terminations. All I usually see is 'into a 50ohm load' and have no real idea how the load can be exactly terminated in that way. It's all new, apologies for that.

TK - OMG, as they say, yes of course. The scope is usually over at the usual bench, but I tend to move it to the far cleaner table for vids etc. The usual scope lead was over at the other bench, so I grabbed another and...didn't check whether it was on 1x or 10x


All - Found something of possible interest, which I would have thought would have reared as a fault or feature, but haven't seen it mentioned. The Dr. Stiffler type L3, with 2x AV plugs, an LED and length of floral wire can be used as a tester for mains wiring continuity.
The circuit is shown in the video and there is a positive reaction with wood, believe it or not. Maybe it's because of the humidity here in Oklahoma, but the thing has some very strange properties.

https://www.youtube.com/watch?v=c4hCiUUcZ18

[shylo]

Hi Slider,
That is interesting, how is the floral wire connected? I assume the circuit you showed is showing the 75 turns on tube connected to the diodesor is that the floral wire and you don't show the 75 turn coil?Thanks artv

[erfandl]

Hi Erfandl,

Your finding the current draw is reduced with the 3 crystal and the brightness increases is interesting.      Would you mind using a Pi filter in the battery supply rails? I do not really think your Ampermeter is fooled with the 3 crystals operating though.

Just connect the oscillator positive supply wire to the battery via a 1 mH (1000 uH) choke coil.  And connect one-one 10 or 22 or 47 or 100 nF capacitor across the supply rails on both sides of the choke, thus you form a Pi filter.  Such filter greatly reduces any 13.56 MHZ and higher harmonic frequencies going back towards the battery and your Ampermeter which now should be connected between the battery positive and the positive input of the choke, ok?   
Let me repeat: I do not really assume your Ampermeter shows false currents and that is why you see current reduction...  For the time being I cannot give a logical explanation. 

Gyula

Hi gyula. thanks for reply. can you draw Pi filter circuit ? I cant understand how to build the Pi filter. thanks

[Slider2732]

Shylo - The floral wire connects to the negative lead of the LED.
The other end of it is buried somewhere in the spool it is on.
In practice, you can simply hold the circuit by that point and it will still partially work around mains wiring. The floral wire is like a big clip lead.