what happens between a teslacoil the battery the incadescent bulb and the ground

[woopy]

Thank's Tinman and Forest

Now we are going on the original question of this thread

What seems to hapeen between the Tc, the battery , the bulb, and the ground should  be" capacitive coupling" or stray capacitance or...

Until now i always thought that this "capacitive coupling " was something annoying in electronic circuit, so to me something of small value, and in no case capable of lighting brightly an incandecent bulb.

But it seems that  at high frequency we should be able to "resonate" that small capacitance so the  reactance of this capacitance decreases and so a large current can pass through. thin air!!!

Whaouu! that's interesting

So the difference of the brightness between TK'sbulb and my small chines Tc shoulds be the ability to more or less "resonate" the capacitance all arround us.

Now i think that it is important to study better the phenomena and try to determine how is the electron flow (current) moving in this "pseudo open" environnement?

Thank's to all for contribution

Laurent

[endlessoceans]

But it seems that  at high frequency we should be able to "resonate" that small capacitance so the  reactance of this capacitance decreases and so a large current can pass through. thin air!!!

Whaouu! that's interesting


Now i think that it is important to study better the phenomena and try to determine how is the electron flow (current) moving in this "pseudo open" environnement?

Thank's to all for contribution

Laurent

Woopy

This is nothing new and it has been well studied long time ago.

  the air is NOT so thin......you pump enough energy into any medium and it will conduct.....it all comes down to how much waste there will be....and there IS waste.

I didn't bother with replying to the so called "contradictions" because there was too much nit picking on the terminology.  Basically you had three guys saying much the same thing but getting caught up in the language of how they express it.  HF transmission is an interesting field with many applications and that's why Tesla spent so much time with it.

Also don't lose sight of the fact it was a 4 watt bulb (tiny load).......and not OU.

[woopy]

Woopy

This is nothing new and it has been well studied long time ago.

  the air is NOT so thin......you pump enough energy into any medium and it will conduct.....it all comes down to how much waste there will be....and there IS waste.

I didn't bother with replying to the so called "contradictions" because there was too much nit picking on the terminology.  Basically you had three guys saying much the same thing but getting caught up in the language of how they express it.  HF transmission is an interesting field with many applications and that's why Tesla spent so much time with it.

Also don't lose sight of the fact it was a 4 watt bulb (tiny load).......and not OU.

Hi e o

You say that this is nothing new, and a lot of studies are already made.

To me it is  new and i would  improve my knowledge and i would very much apreciate some  links to the studies you mentionned on the subject.

Many thank's

Laurent

[TeslaScientific]

That is not correct--there is always a path for the current to follow-or flow through.

In this case,it is via capacitive coupling,as shown in all your pictures you posted,where you are one end/plate of that capacitor.

Try lighting your incandescent bulb's without touching them,or having a can(as a cap plate) attached to one end of the bulb--you will see that it will either not light at all,or it will be extremely dull,where the bulb casing itself is acting as a small capacitor plate.

At high frequencies,even the smallest value of capacitance can deliver high amounts of current-even when that path is through the air.

Your incandescent bulb's(and i suspect the same with TKs setup),are being lit due to capacitive coupling,which completes the path for current to flow,and where the air around you is the dielectric between the capacitor plates(you and the circuit).


Brad

It definitely has nothing to do with capacitive coupling. It IS a ONE WIRE SINGLE POLE system. The capacitance doesn't couple any energy. Putting a small capacitor across the bulb would do the same. It's only a "load" that the energy will reflect from. When the bulb filament is the end of the transmission line, of course it doesn't light, why should it? Why should the energy flow through the filament and heat it up to produce light? When you put a terminating capacitance AFTER the filament, now the energy flows THROUGH the filament, and it lights. 100% NOT capacitive coupling. It's absolutely based on the fact that the energy is reflecting back and forth within the terminating bounds of the transmission line, just like the Bell Labs video shows. The bulb filament happens to be at some point along that transmission line, so the oscillating energy is flowing through it, and so it lights. No "ground" or "return loop" or "capacitive coupling" necessary. The "ground" is the one and only, live terminal.

Inconvenient fact #1: Capacitive coupling depends on the capacitance. The capacitance depends on the distance. Unfortunately for some speculations and hypotheses, the distance from the coil makes no difference whatsoever. Hence the capacitance makes no difference whatsoever. Hence it is not capacitive coupling.

Inconvenient fact #2: Radiated energy is governed by the inverse square law. 1/distance squared. Double the distance, quarter the power. I double the distance, and I get the same amount of power. Why? Because the energy is only going through the wire.

Even if Tesla himself told you what was happening, someone out there would still argue back and tell him that he's wrong.

http://www.tfcbooks.com/tesla/1908-00-00.htm

https://teslauniverse.com/nikola-tesla/articles/famous-scientific-illusions

http://www.tfcbooks.com/tesla/nt_on_ac.htm

http://www.tfcbooks.com/tesla/1919-05-00.htm

[tinman]

It definitely has nothing to do with capacitive coupling. It IS a ONE WIRE SINGLE POLE system. The capacitance doesn't couple any energy. Putting a small capacitor across the bulb would do the same. It's only a "load" that the energy will reflect from. When the bulb filament is the end of the transmission line, of course it doesn't light, why should it? Why should the energy flow through the filament and heat it up to produce light? When you put a terminating capacitance AFTER the filament, now the energy flows THROUGH the filament, and it lights. 100% NOT capacitive coupling. It's absolutely based on the fact that the energy is reflecting back and forth within the terminating bounds of the transmission line, just like the Bell Labs video shows. The bulb filament happens to be at some point along that transmission line, so the oscillating energy is flowing through it, and so it lights. No "ground" or "return loop" or "capacitive coupling" necessary. The "ground" is the one and only, live terminal.

Inconvenient fact #1: Capacitive coupling depends on the capacitance. The capacitance depends on the distance. Unfortunately for some speculations and hypotheses, the distance from the coil makes no difference whatsoever. Hence the capacitance makes no difference whatsoever. Hence it is not capacitive coupling.

Inconvenient fact #2: Radiated energy is governed by the inverse square law. 1/distance squared. Double the distance, quarter the power. I double the distance, and I get the same amount of power. Why? Because the energy is only going through the wire.

Even if Tesla himself told you what was happening, someone out there would still argue back and tell him that he's wrong.

http://www.tfcbooks.com/tesla/1908-00-00.htm

https://teslauniverse.com/nikola-tesla/articles/famous-scientific-illusions

http://www.tfcbooks.com/tesla/nt_on_ac.htm

http://www.tfcbooks.com/tesla/1919-05-00.htm

Perhaps you should study up on ground plane's a little.


Brad