Why this seesaw is working against physics laws

[vikram_gupta11]

Changes are essential as the experiment s are indicating that I will have to do some changes to get overunity.
This is the final design.

See the sketch.

As per sketch there will two arms and two fulcrum.both arms will be separated with each other by minimal distance.

The counterweight is 1.2 kg and ball weight is 1 kg.

The tube length is 50 cm.the total arm length is 70 cm.

Now mathematical proof.

Consider in it an inelastic collision.

Initial data:

m1=1 kg

M2=1.2kg

V1=3.33m/s

Kinetic energy=5.54joule

Final value:

V2=1.51m/s

Kinetic energy=2.52 joule

Amount of kinetic energy lost in collision is=3.02 joule

Ratio of kinetic energy before and after Collision=0.45

Fraction of kinetic energy lost in the collision=0.54

So input energy will be

Mgh=0.2*10*0.35

Input=0.70 joule

Why,because the arm length and mass distance is equal from fulcrum but there is only 200 gram weight difference.

There is an another very interesting point.

The counterweight will compress a spring when the ball is in air .once ball hit the bottom of tube then the spring will release its energy and device will turn with great momentum.

[vikram_gupta11]

Dear Sir,
There are two fulcrum A and B.
An orange color ball is in resting position on fulcrum B and a green color counterweight is resting on fulcrum A as per sketch.
The mass of ball is 1 kg.
The mass of counterweight is 1.2 kg.
There are two spring based brake system and only counterweight will hit with these spring brakes.
How it will work?
The initial position of device will be 178 degree.
So when we tilt it at 180 degree then the ball will be dropped down and hit with the bottom of tube of fulcrum A.
Due to impact a " spring based latch mechanism" will work to hold the ball from reverse falling down at the time when the arm will rotate clockwise.
Counterweight will also move from arm A to arm b.
In this way the ball will get back it's initial or even more height than the dropping point.
Now see the second sketch.
The ball will fall down again and the same thing will be happened but the arm will rotate anticlockwise.
The friction heat air resistance are not issues as both mass are exchanging their position from one system to another.
In this way this mechanism will work.
The latch pin mechanism will work in this way that it will lock and unlock due to mechanical power.

[vikram_gupta11]

The center of gravity will be always in line with fulcrum due to changing position of fulcrum so the design will work.

[vikram_gupta11]

As per video the seesaw will be mounted on this kind of rotating wheel/ disc.

https://youtu.be/SikOJblbhV0
The disc will rotate back and forth.

Now see the sketch.

The counterweight will be some heavy than the ball.

The tube of counterweight will be like "U" shape.



Now see the design of tube of ball .

There are sliding point on the both side of tube .

The design of long tube will be work in this way that the ball will fall down after getting a certain angle.

The device will be mounted in middle of disc.

Measurements.

The length of long tube is =50 cm.

The length of tube of counterweight is ,

The curved arms =20 cm.

The straight arm=10cm.

The counterweight will be also a ball.

Mechanism:

When ball will fall down then it will hit the bottom of tube an due to it's kinetic energy the device will rotate and the ball will get back it's initial position or even more height than the dropping point.

The curved shape of tube of counterweight will work in this way that the movement of counterweig ht ball will work to provide the momentum.

The same mechanics will work again when ball will again fall down.

The disc will rotate clockwise and anticlockwise.

I would like to insist on the rotating mechanism of disc as it is very important in it as there is no pivot point in it.

I have tested it and it will work.

If you could design the disc using with ball bearing then it will work beyond our expectation.

At first you please test it without design the tubes with a long tube and drop a ball from some height.

The ball will get back it's initial height.

I want that you please use spring based lock or brake system to prevent the device from further movement.

Though we can use secondary lever system instead of spring but at first test it with spring.



All things are same except there is a disc which will oscillate due to impact energy of ball.

[vikram_gupta11]

I tested it and ball is getting more height than the dropping point.
https://youtu.be/ajQVngShPkc
https://youtu.be/PFBS9ddiNRE
Please don't consider the lifting point as there is no brake to prevent the falling of counterweight.
The initial position of device will be 179 degree.