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Overunity Machines Forum



Building The Clem Engine Series

Started by TommeyLReed, November 01, 2017, 09:54:17 AM

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ramset

I believe your recommendation and  many similar have been done over the years [by Tom] ,

he is doing empirical testing thru actual builds.. and has been for quite some time.

an amazing amount of work.
and he is seeing positive results!!

respectfully

Chet K

Whats for yah ne're go bye yah
Thanks Grandma

conradelektro

Quote from: Ronnachai on November 06, 2017, 11:26:02 PM
I'm looking for information on The Clem Engine Series.

https://www.youtube.com/watch?v=-OzcUp7i5sk   interesting drawings starting at minute 5:19

This video seems to show that only the disk shaped element is important and that a simple pipe sucks up the fluid (no vortex in a cone shaped element).

But a vortex provides nice esoterics which is always good for creating interest.

The Clem Engine is known as "contrifugal pump" https://www.youtube.com/watch?v=BaEHVpKc-1Q

A well working centrifugal pump has to be filled with fluid in order to start pumping. If one wants starting with air (fluid not yet in the pump at start up) one has to build a less effective pump.

Since TommeyLReed wants start up with air, he has to use slimmer ducts in the disk shaped element. He could use wider ducts in the disk shaped element (better pumping efficiency) if he filled the disk shaped element with water prior to start up.

Greetings, Conrad

TommeyLReed

Hi Conrad,

Thank you for your information and comments.

What if a 7 stage pump as Richard Clem's claim his system used?

Do you really need a average external pump to generate pressure for the rim jets or can it be built more efficient as a single unit?

We re about to find out with this new 6 stage pump design. I'm building this with my 3d printer as a experiment with even 4 rim jets to test one of many claims of the Clem engine.

My design.
https://www.youtube.com/watch?v=MPFHpSn2doI&feature=youtu.be

Great video to verify my design.
https://www.youtube.com/watch?v=guATpg2drs4

Tom

conradelektro

Quote from: TommeyLReed on November 11, 2017, 08:09:29 AM

What if a 7 stage pump as Richard Clem's claim his system used?

We re about to find out with this new 6 stage pump design. I'm building this with my 3d printer as a experiment with even 4 rim jets to test one of many claims of the Clem engine.


A 3D printer is a wonderful tool to build these rotors. Sooner or later I have to buy one.

I do not want to play the wise guy, but "7 stage pump" is not the right expression. It should be named "7 fold pump".

Arranging pumps in"stages" would increase the pressure from one pump to the next. A "7 fold pump" (the Clem design) does not increase the pressure but the throughput. A "7 fold pump" would increase the throughput times 7 (would pump 7 times more liquid than a single pump).

Each rotor (the disk shaped element) of the "7 fold pump" or "6 fold pump" sucks with the same intensity (due to the centrifugal force imparted on the liquid in the rotor ducts). Each rotor creates the same centrifugal force. The centrifugal force depends on the speed of the rotation, the diameter of the disk and the weight of the liquid.

Greetings, Conrad

TommeyLReed


"Arranging pumps in"stages" would increase the pressure from one pump to the next. A "7 fold pump" (the Clem design) does not increase the pressure but the throughput. A "7 fold pump" would increase the throughput times 7 (would pump 7 times more liquid than a single pump)."


Well, who really knows how the Clem engine was built? what little information is out there nobody has yet created a single working version.

The questions is how many gpm and rim jet thrust will it take to over come the rotation drag?

Thrust has too factors of the diameter of the rim jet and the flow rate that end up in amount of pressure needed.

In water rockets the formula of: "1.57*psi*d*d" is the force of the rim jet.
So, a 100 psi at a rim jet of .25 diameter would produce a thrust of 9.81lb.

The max speed of that thrust would be about sqrt(32+32*(psi/4.33)) =86.15ft/sec

So (86.15ft/sec*60)= 5169ft/min
The area of the rim jet is (pi*r^2)= 0.49
Flow rate = 5169*0.49/231=10.96 GPM
10.96*100/1714=0.64 mechanical hp needed to produce movement.

Next question is how big, 12" diameter would spin faster then a 24" diameter that would have greater torque but less speed.
12" diameter would produce about a (5169ft/min/3.14')= 1669 rpm max with no load not counting on wind drag and friction.
Even at half that speed 834.5 rpm the max torque load would be 4.9 foot pound or (834.5*4.9/5252)= .78 hp-15%-20%drag.

In other words I can't see rim jets running the Clem engine, that's why I went with hydraulics.

Thanks for the comments