Confirmation of OU devices and claims

[seaad]

You can maybe build an OU
NE-2 Ring Counter 
N.B. You use 100 Volt input and 1 Mega Ohm series resistors (tiny current).
"A NE-2 is a very low-current device !"

http://www.bristolwatch.com/ele/neon.htm

Arne

[itsu]

Benfr,

Simply said, if you can multiply voltage while keeping the same amperage, you have therefore overunity.

I wish it would be that simple, but besides voltage, current and power, there are also things like phase, real power, reactive power, etc.
Please take a look at how AC power is derived here:
http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html

And why there is such a high voltage across C or L (but 180° out of phase, so canceled) in a series LRC circuit here:
https://www.quora.com/Why-is-the-voltage-drop-across-the-inductor-L-and-the-capacitor-C-much-larger-than-the-applied-voltage-in-a-series-of-resonance-circuits

Itsu

[AlienGrey]

Hi3 pages back re Rick F and his fancy 50 dollar 157uhry coils one guy finds a junk RC calculator that ets a 100uf cap to resonate at 1 khz, is that a joke or what ?


https://www.1728.org/resfreq.htm
Resonant Frequency Calculator


anyway, see pic!

[gyulasun]

Hi benfr,

Unfortunately, you misunderstand the operation of a series LC circuit.  In the tutorial url link you referred to, there is nothing which would imply:  "if you can multiply voltage while keeping the same amperage, you have therefore overunity." 

Try to estimate how much power your neon bulb consumes. Here is a data sheet http://www.farnell.com/datasheets/57560.pdf on it, page 2,  NE-2 draws 0.6 mA and breakdown voltage is betwen 60 to 90 VDC. 
Lets choose say 75 V, divided by 0.6 mA gives 125 kOhm, ok? This is the load for you resonant circuit WHENEVER the instanteneous AC voltage across the coil (or capacitor) exceeds 75 V. Now estimate that out of a full cycle, T=0.809 us (T=1/1235kHz), how many us (microsecond) part of the sine wave is under +/-75V, and how many us part of the sine wave exceeds +/-75V (suppose your sine wave across L or C has say 110 Vpp)?  because current can flow through the bulb only when voltage difference across it exceeds 75V.  The ON time for the bulb versus the OFF time is way less time duration within a T period, this means that even the very small 0.6 mA load current is flowing for say 1/3 or 1/4 of the T time period. 
Try to use an incandescent lamp (or a fix resistor as I suggested to member A.king) which will will be present during 100% of the T time period (except at zero crossings of course) and then see the real performance.  With neon bulb you have some hundred microwatt output power versus the some ten milliwatt input your function generator feeds into your circuit.

This leads you to study the meaning of peak and average power in an LC circuit.   

Have a look at this circuit  http://www.discovercircuits.com/DJ-Circuits/ac14fls.htm   
where a pulsed LED lamp is fed from a 1.5V battery and see what a big difference can exist between peak LED current and average LED current, hence peak power and average power drawn from the battery. It is the average current which counts on the long term of course and defines battery life time.  The 20 mA peak current flows only for 400 usec in that circuit at each ON time.

Overunity which is a misnomer, (better use efficiency or COP), should be used to compare the average input power (or energy) to the average output power (or energy) a device supplies to your load as useful output.
Efficiency or COP (or the misused name overunity) is never used for comparing only input voltage (or current) to output voltage (or current), it is a mistake, always average power levels should be used.

Gyula

[gyulasun]

Hi3 pages back re Rick F and his fancy 50 dollar 157uhry coils one guy finds a junk RC calculator that ets a 100uf cap to resonate at 1 khz, is that a joke or what ?


https://www.1728.org/resfreq.htm
Resonant Frequency Calculator


anyway, see pic!

Please give more details,  where is 1 kHz and where is 100 uF in these LC circuits involved? Who wrote that, give Reply #
Gyula