The secret to Overunity

[Tajerek]

What you are saying is the amount of water in a glass has nothing to do with the amount of water that ran from the faucet.

No that's not what I am saying, what I say is the amount of water in the glass is related to the difference of POTENTIAL of the water and the glass, the quantity of the water source  ie. the voltage. Not the current.
It is not me who claim that, it is known formula that energy in capacitor doesn't depend on the current of the source.

I know it sounds strange but that's why it is the secret. You may read the quote of Tesla that I mentioned.

Charge on capacitor Q = C* V_source*[1-Exponential(-t/RC)]   --> the source current doesn't factor here

[citfta]

You are very confused about the relationship between voltage and current.  To properly relate it to the water analogy, the voltage is the pressure and the current is the quantity of water.  So your statement about the quantity of the water source being the same as the voltage is wrong.  To charge a capacitor to a higher voltage requires more energy.  You keep insisting it doesn't and that is where you are wrong.

I am done here.  It is clear you are not interested in learning why you are wrong.  You are going to have to build it yourself and then you will understand that it doesn't work like you want to believe it will.  Good luck.

Respectfully,
Carroll

[sm0ky2]

What Tesla was talking about was a high-voltage (leyden jar type)
rolled foil condenser. While technically the same, these are not
like the low voltage capacitors we use today.


These were usually made with a wax in between the layers.
Later ones had a type of plastic, and metal casings were put around
them for safety in automobile ignition circuits.


The first photo shows the rolled type Tesla was mentioning
The second one shows a 1906 device demonstrating that they are
used as electron+positron pairs.


We use the earth sink as the positron source. So we don't have to deal
with all that pesky 1/2 of the energy we use.

[Void]

You are going to have to build it yourself and then you will understand that it doesn't work like you want to believe it will.  Good luck.

Aye, anyone who has only done even the most basic of testing with capacitors would understand
that what Tajerek is saying here is based on misunderstanding of basic concepts. It takes energy
to charge up a capacitor. That energy has to come from somewhere. The suggestion that
applying high voltage to a capacitor will somehow magically cause a capacitor to charge up
without expending equivalent energy is simply not going to happen, *at least not under normal
conditions*. Something very unusual would have to be happening if a cap can charge up without
expending energy from the input power source that is being applied to the capacitor.

Yes, it seems pointless to explain things further when someone is not willing to give
due consideration to what is being said.

All the best...

[sm0ky2]

Trying to locate the reference, but Tesla talked about how to discharge the condenser
Through a coil transformer and back to the condenser, reversing polarities.
Basically dumping it back onto the opposite plate after running it through the inductor.
This would cause it to continue to oscillate for a long time.


When you place a charge onto a capacitor plate, the other place will induce its own charge.
It doesn't matter which plate or which polarity you choose.
It can be either plate, and + or - charge.
The real power (current part of the equation) comes from both charges.
Not just the charge you supply.


It's opposite is drawn in from the environment


We use brute force technology instead of allowing the natural energy to flow.