12 times more output than input, dual mechanical oscillation system !

[Low-Q]

Maybe this post will end this thread :-). I made a pendulum with  a magnet on it. The magnet pass a stationary iron powder core and the pendulum is fluctuating nicely - not doing work. Then the core is free to move in the magnetic field - the pendulum are doing work, but stops right away.

The point is that gravity cannot apply energy.http://youtu.be/pDvTpIoHJaI

[ltseung888]

perhaps you should read the rest of this thread, we went over this around the first 20 pages.....

but a short recap on that if you must....

The Kinetic energy(1/2mv^2) and Potential energy (mg*length[1-cos(swing angle)]) of the swinging pendulum always balance each other out, regardless of pendulum mass.
At bottom dead center, however, the force is perpendicular to the swinging pendulum, and E = mgh of the 2nd fulcrum weight is subtracted
from the motion of the pendulum, the energy being subtracted from each side of it's swing ( minus all other appropriate losses).
This results in lower swing height on each successive swing, and thus the pendulum stops.

This is easily demonstrated using two identical pendulums, one WITH a 2nd fulcrum weight, and one WITHOUT.
Start both pendulums swinging in synchronicity, while the 2nd fulcrum weight is held in place, and you will see that both pendulums behave exactly the same.
However, when you release the 2nd fulcrum weight, the second pendulum slows down, and eventually comes to a stop.

Now let's Lead this conversation OUT to the water wells, where this device is used as a pump, by it's inventor::
this pump requires energy INPUT, to keep it running. The specs are available on his company's website.

As I expected, your calculation never considered the effect of Centrifugal Force.  Please recheck your calculations.

[Low-Q]

As I expected, your calculation never considered the effect of Centrifugal Force.  Please recheck your calculations.

A centrifugal force poses no load to the system, hence it cannot be considered to be a contributor to do work.


Vidar

[Low-Q]

Where?

Here:
http://www.overunity.com/15090/dry-friction-and-the-milkovic-effect/


Vidar

[Paul-R]

Reactive power poses no load and can not be converted to do work.

I thought that this is questioned, and is thought to be a basis for OU. (EVGRAY yahoo group etc).