12 times more output than input, dual mechanical oscillation system !

[astroshima]

I think that instead Ep= m*g*h we will have Ep=m*g*dh (dh=height differential) which is the same formula.
BTW you need here precise strokes to the pendulum + very accurate (slow motion mode) camera with visual scale measuring system + error of the measurement as approximation of the last pendulum swing angle recorded by the camera in slow motion mode...

Or (maybe) even simpler and more easy to measure:
1. When pendulum fulcrum reach starting point (= maximum height) (and lever arm weight is in contact with the base so it has minimum heigth h=0)
and
2. when pendulum weight reach appropriate angle-amplitude
then just:
3. Grab the pendulum weight with hand and
4. lift it for some height: dh (or h) (dE= m*g*dh)
5. repeat this energy input when necessary

[Merg]

Can anyone explain me how we will calculate the output energy of generator in case of using E=mgdh for input energy??? If I attach simple wattmeter it cannot show me precise output energy cause volts and amperes will vary (decrease) during the work of oscillator.

Since we read above that pendulum amplitude will decrease during the time - it means the lever movement will decrease too.
Does anyone know any measuring device that can calculate output power graph where volts and amperes vary? We will have the output result as an output graph and I suppose we need some clever software to calculate output energy from this graph in the unit of time e.g. 10 secons or 1 minute.

We need constant oscillation of pendulum to precisely measure the output energy.

[TinselKoala]

The very best way that I can think of, without a fancy and expensive DSO, is to run your output current through a resistor immersed in, say, water, and then look at the temperature change in the water. The water acts as an "integrator" that stores and sums the incremental Joule heating caused by the volt-amps from the source flowing thru the resistance, however much they vary over time.
There is some math involved and things have to be done precisely, but in principle it is something that the home experimenter should be able to do fairly accurately.

Using this technique (which is basically Joule's method) you don't even need to convert the output to electricity first. With a suitable mechanical arrangement, the water can be stirred directly by the mechanical oscillator's output and the heating measured.
In theory, anyway.

Another way to do it, the old timer's way, is to display the curren t( ie voltage drop across a known resistence) and voltage waveforms on an ordinary scope, then trace the waveforms on tracing paper, cut out the appropriate segments and weigh them on an accurate scale. This process is equivalent to integration. Some math magic, and voila!

[sm0ky2]

apparently someone must intervene here, because this malkovich pump is being analyzed in completely the wrong way......

the energy of the pendulum is well known, and most seem to grasp the understanding of this.

BUT - the force acting on the lever arm is causing a whole lot of unnecessary confusion.
allow me to clear this up::::

Force (downward) causes the action of the lever.  <-- this is the force we must calculate.
the 'reset' (upward) is caused by the other end of the lever arm being heavier, and does not affect the energy value of the pendulum.

The equation that gives you the downward power of each swing is the equation for Tension (Force) on the rod, for a duration of T ( where T is the duration of time it takes the pendulum to pass 1 radian at maximum velocity @ bottom dead center) 
Tension is often overlooked, for the simple fact that most pendulums are constructed on a rigid fulcrum, and Tension normally has no effective value.
Tension is represented by:     Tens =  [ mv^2 / r ] + m g (3 cos {} - 2)
     Where:  m = mass
                 v = velocity
                 r = rod length (or radius)
                 g = gravity
           and {} = 0 @ bottom dead center

The tangential force on the pendulum is effectively 0 @ bottom dead center and can be ignored.
   This is due to the angle from verticle being itsef 0.

  Thus:  E =  (T * Tension)
         where E is the energy of each lever action.
                   T = duration for pendulum to pass 1 radian @ max velocity

example:
if you raise a given pendulum and let it swing , and it oscillates 100 swings,
   then:  E(average) =  MGH/100
   where E =  energy of each lever action
     MGH is that of the original pendulum bob when raised to its starting position.
In practice, E is max on the first swing, and decreases slightly with each swing, and eventually ends up at 0 when the pendulum stops.
This is observed when the pumps are used by the decrease in water-flow*pressure as the pendulum slows down.


This extracted energy does not affect the swinging of the pendulum, but is rather a derrivitive thereof.
it is essentially re-obtaining the energy from the natural decelleration of the pendulum in a unique way.
The total energy value is = to that obtained by an identicle impact hammer.
This device is not "overunity". it's "overconvenient", at least for the purposes for which it is used.
It is quite possibly the most efficient method of energy transfer we have to date.

I hope this clears everything up. if anyone needs further explanation, feel free to ask.

[Talmin]

"Mechanical Fission: Two-stage mechanical oscillators should be set in accordance with geometry progression system, by which mechanical chain reaction could be achieved: 1<2<4<8< oscillators...
This could be the best way to confirm the overunity effect and accomplish replacement for nuclear fission."

hmm interesting thinking - mechanical fission!