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Overunity Machines Forum



12 times more output than input, dual mechanical oscillation system !

Started by hartiberlin, November 30, 2006, 06:11:41 PM

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0 Members and 85 Guests are viewing this topic.

tagor

Quote from: exnihiloest on August 27, 2009, 03:45:27 AM
It is damped by the load.
When at the lowest position, an ordinary pendulum mass has lost its potential energy. It can regain it by continuing its movement and transforming again its kinetic energy into potential energy, by moving up to the same height it was starting from.

But the Milkovic's pendulum is different. When the pendulum mass is at the lowest position, the fulcrum is at a lower position due to the movement of the lever. The pendulum mass has lost a supplementary potential energy. In order the pendulum mass to regain this potential energy, the lever must raise again the pendulum fulcrum by restoring the energy it acquired from the lowering of the pendulum mass (that one due to the lowering of the fulcrum). If energy is consumed at the other end of the lever, the lever will lack energy to restore the position of the fulcrum at the same height.

The Milkovic's pendulum is really a parametric pendulum with a pumping function. Nevertheless in such a system, the energy is always conserved, it is just shifted from the pumping system at the pumping frequency to the pumped system at the pumped frequency (for example, search for "parametric amplifier". http://en.wikipedia.org/wiki/Parametric_oscillator. They were used in the 60's to amplify SHF signal received from big parabolic satellite antennas, by pumping a variable capacity of an oscillating LC circuit and thus transfering the energy from the pumping frequency to the signal frequency).

thank you exnihiloest


tagor


Charlie_V

QuoteIn the Milkovic example, the pendulum is not damped by the load, and so it can be fed back. 

What i meant to say is that the ALTERED Milkovic example is not damped.  Yes both Tagor and Exnihiloest are correct - the standard Milkovic example has dampening because the pivot point drops as the pendulum swings downward.  This takes energy from the system, Exnihiloest your explanation is perfect.

QuoteThe Milkovic's pendulum is really a parametric pendulum with a pumping function. Nevertheless in such a system, the energy is always conserved, it is just shifted from the pumping system at the pumping frequency to the pumped system at the pumped frequency (for example, search for "parametric amplifier".

The key here is when properly designed gravity does the pumping.  Right now because the pivot point moves, gravity is only doing some fraction of the pumping, the operator of the pendulum does the rest.  If the pivot point doesn't move, gravity will do 100% of the pumping.  This is a very interesting result. 

And yes energy is conserved because the output is the initial energy input plus the energy required to keep the pendulum swinging.  But if Bob puts in the initial energy, and Mike keeps it swinging, it will appear to Mike that the device is over unity (assuming the device is designed so that the pivot point doesn't move).  Mike will think this because he is oblivious to the initial energy input that Bob placed.  So to Mike, the output (Bob energy + Mike energy) is much more than Mike's input. 

The damping of the pendulum is the most important aspect.  If you can never remove the pendulum damping, I don't think it will ever be possible to feed the energy back.

Solomon111

However, the advantage of this device is simple, so the friction is minimal, also the losses are minimal!
A overunity (energy surplus) have been confirmed by many!
See the previous pages!