Kapanadze and other FE discussion

[rakarskiy]

https://rakatskiy.blogspot.com/2017/07/free-energy-system-generator.html

[Sergh]

Says that: this wire serves as waveguide for the  wave that  goes along the wire.
here:  https://youtu.be/ZckaMOlixqw?t=105

These people made the "discovery" or the assumption that metals have a gigantic, almost infinitely great dielectric constant. Probably hoping that it is impossible to prove both this and the opposite because of the high conductivity of metals.
And in their opinion, the alternating current propagates through the conductor as through the dielectric of a capacitor with an infinitely large capacitance. From this proceed their other conclusions about propagation along the wire. They probably read a books about microwaves, about the Goubau line, but did not pay attention to the huge difference in frequencies.
I don't understand how much they enjoy it.

In that particular  Russian video  we see however  generator  not more that 500kHz max having two outputs  and using only one  of them  that is giving out  sinusoidal signal.
The  generator has maximum voltage of 5V  but I'm not sure  about  what the dial switch set on 20, on the left to the V-meter   is for?
The generator is set on the video to 1kHz
(Please look at the picture below)
https://overunity.com/17735/kapanadze-and-other-fe-discussion/dlattach/attach/192526/image//
Wesley

From these pictures, I can assume that the generator produces 8 kilohertz at the output.  From the pictures you can see that this is the number 8 multiplied by 10^3.
The switch performs the function of an output signal attenuator. That is, in this position, it should decrease the output signal level by 20 decibels, about 10 times in voltage amplitude. This is maximum 0,5 V on 600 Ohm load or 1.0 V with no load.
But I see on the bottom photo that the attenuator knob is set to 10 decibels, which means that under load the output can be up to 1.6 volts, and without load up to 3.16 volts.
A variable resistor under the voltmeter can adjust the amplitude under load from 1 to 5 volts, probably without load it will be from 2 to 10 volts. It is set to a position close to the minimum. Probably, the amplitude is set by the voltmeter with a variable resistor, and with a step attenuator it is additionally lowered if necessary.
Conclusions: the generator output is connected to a load of more than 600 ohms.
The output voltage is less than 0.5 volts.

Here is a  video of Russian  butcher  who made me angry:
https://www.youtube.com/watch?v=AyR9KwbOqN0

I don't care. Someone needs to dispose of the old scrap. Soviet measuring instruments were often of poor quality even in their youth.

[stivep]

From this proceed their other conclusions about propagation along the wire. They probably read a books about microwaves, about the Goubau line, but did not pay attention to the huge difference in frequencies.

Very good point I agree.
But than a question would be why frequency must be high?
Dr James Corum did all of these tests.
144MHz then 52MHz then 1.8 MHz then 132kHz and then 18kHz for Surface Zenneck Wave in the interface.
_____________________________

From these pictures, I can assume that the generator produces 8 kilohertz at the output.  From the pictures you can see that this is the number 8 multiplied by 10^3.

Yes  I do apologize0 -  that what look for me  like 0 is in  reality 8.
So yes the frequency they used is 8kHz.

The switch performs the function of an output signal attenuator. That is, in this position, it should decrease the output signal level by 20 decibels, about 10 times in voltage amplitude. This is maximum 0,5 V on 600 Ohm load or 1.0 V with no load.
But I see on the bottom photo that the attenuator knob is set to 10 decibels, which means that under load the output can be up to 1.6 volts, and without load up to 3.16 volts.

Again good  point. Thank you  but I have problem with 600 ohm.

A variable resistor under the voltmeter can adjust the amplitude under load from 1 to 5 volts, probably without load it will be from 2 to 10 volts. It is set to a position close to the minimum. Probably, the amplitude is set by the voltmeter with a variable resistor, and with a step attenuator it is additionally lowered if necessary.

I agree.

Conclusions: the generator output is connected to a load of more than 600 ohms.
The output voltage is less than 0.5 volts

The output impedance  at BNC is  is 50 Ohm not 600 Ohm.

I don't care. Someone needs to dispose of the old scrap.
Soviet measuring instruments were often of poor quality even in their youth.

I must disagree.
In Russia there are plenty of children and young  students who would be happy to have such
tool.
Wesley

[stivep]

https://rakatskiy.blogspot.com/2017/07/free-energy-system-generator.html

good lecture thank you.
https://patents-google-com.translate.goog/patent/US3289015?_x_tr_sl=ru&_x_tr_tl=en&_x_tr_hl=ru&_x_tr_pto=wapp&_x_tr_hist=true
Wesley

[Sergh]

The output impedance  at BNC is  is 50 Ohm not 600 Ohm.

The designers of these low-frequency generators did not pay attention to the impedance of the connector. They just used it as a connector. At such low frequencies, the impedance of the connector does not matter much.

There is official documentation for this generator:

https://rw6ase.narod.ru/index1/pribor/generator/g3_120.djvu

It states that the nominal load resistance for this generator is 600 ohms. With this load resistance, the generator has a maximum voltage of 5 volts at the output. Without load, meaning at a load of much greater resistance, for example 1 megaohm, the output can be up to 10 volts.
When the resistance is less than 600 ohms, the output voltage decreases. This can be calculated using formula 8.1 from the documentation on page 20. In any case, the current in the load must not exceed 0.008 Amperes, otherwise it may lead to a malfunction of the device.

But than a question would be why frequency must be high?
Dr James Corum did all of these tests.
144MHz then 52MHz then 1.8 MHz then 132kHz and then 18kHz for Surface Zenneck Wave in the interface.

Estimate the size of these surface waves for a frequency of 10 kilohertz. They will be many times the length of the entire wire and the free space around. And how can it work? These guys will not get any low-frequency surface waves at all.

If they pulled their wire between the Moon and the Earth, then maybe it would work like the Goubau line. But you would also need cyclopean horns at the ends of this conductor to transform the impedances.

If you are going to create low frequency waves on the surface of the Earth - then ok. You are using a planetary scale and you need an appropriate huge system to create them. Like Tesla's Wardenclyffe Tower.