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Overunity Machines Forum



IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?

Started by George1, July 21, 2018, 08:11:37 AM

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nix85

QuoteI have a levitation machine

Funny. Let me guess, all cameras suddenly break when you try to film it.

QuoteAnd it doesn't use your "basic principle"

All inertial propulsion devices ever built and that ever shall be built use it.

QuoteOne of the biggest obstacles to having this field accepted is the word 'reactionless'..

No it's not, everyone knows very well it just implies not reacting with outside matter or force.

QuoteNow tell us all about the Conservation of Momentum, and display an absence of understanding.

Overall energy in creation is 0, everything is conserved. As for lack of understanding it sure abounds on your side

lancaIV

https://www.google.com/search?q=jerry+volland+aetherforce&rlz=1C1AVFC_enPT930PT930&ei=sNthYMGVIK-j1fAPtKuF-Ac&oq=jerry+volland+aetherforce&gs_lcp=Cgdnd3Mtd2l6EAw6DQgAEMcBEK8BELADEA06CQgAELADEAoQHjoJCAAQsAMQDRAeUPwiWM9DYPdTaAFwAHgAgAG4AYgBqQySAQM2LjmYAQCgAQGqAQdnd3Mtd2l6yAEIwAEB&sclient=gws-wiz&ved=0ahUKEwjBrcmT09XvAhWvURUIHbRVAX8Q4dUDCA0


about ZPE or https://de.wikipedia.org/wiki/Nullpunktsenergie


In the classical case, the state of lowest energy is that in which the particle is at rest at {\ displaystyle x = 0} x = 0, i.e. {\ displaystyle p = 0} p = 0. In quantum mechanics, however, the uncertainty relation between position and momentum prohibits both quantities from having exact values. The more precisely the location is known, the less precisely the impulse is known and vice versa. The zero point energy is clearly shown as the mean value of these fluctuations.

THE MEAN VALUE BETWEEN POSITION AND MOMENTUM

nix85

I'm gonna share again the design i came up with, not the first who came up with it tho.

Advantage of this system is it doesn't need a ferrofluid.

There is a better way to do this with much less water in useless bottom part, but principle is the same.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

imagine a circular pipe, bottom half 4 times the diameter of the upper,

there is a pump inside the system,

in short, centrifugal force will be 4 x greater in upper part despite the

fact that volume of water is 4 times less.

this is due to venturi effect (continuity principle), water in narrower part

speeds up proportionally to how much narrower pipe is (https://youtu.be/UJ3-Zm1wbIQ?t=97 )

and centrifugal force is proportional to velocity squared.

let's say 5 liters is enclosed in the tube, since upper half is 1/4 diameter,

there are 4 liters in bottom half and 1 liter in upper half.

let's say pump is pushing bottom part water at 1m/s, this means water

in upper part moves at 4m/s.

let's say radius of the circle is 0.5m

let's calculate the centrifugal force http://www.calctool.org/CALC/phys/newtonian/centrifugal

for 4 liters at 1m/s force is 8N or 0.8kg.

for 1 liter at 4m/s force is 32N or 3.2kg.

or constant 2.4kg, but since only at the center force is pure y component it is 1/2 or 1.2kg average up


and

for 4 liters at 2.5m/s force is 50N or 5kg.

for 1 liter at 10m/s force is 200N or 20kg.

or constant 1/2 x 15kg = 7.5kg up

etc

of course increase of velocity means more friction and very low friction tube

must be used, like electropolished stainless steel, but principle is clear and should be tested.

nix85

You build scrap, i build sophisticated stuff.

I've seen your "levitation" video. Better tie it down so it doesn't fly away.

Basic principle always stands.

nix85

Oh it's "secret", i see :)

Understand the basic principle, 4th law of motion.