IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?

[George1]

To Floor.
====================================
Asking my two simple questions for the 27th time.
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
Looking forward to your two answers for the 27th time.

[George1]

To Floor.
==========================
Asking my two simple questions for the 28th time
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1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
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2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;   
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can replaced by any other curve patterns.
--------------------------------------------
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
---------------------------------------------
Looking forward to your two answers for the 28th time.
===========================
P.S. Dear Floor! Dear colleague! Don't be afraid of truth! Don't be a coward! Tell your masters to mind their own business and be an honest and courageous person! Be a brave and courageous warrior! Like any member of our team!

[George1]

Asking my two simple questions for the 29th time
--------------------------------------------
1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
--------------------------------------------
2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;   
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can replaced by any other curve patterns.
--------------------------------------------
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
---------------------------------------------
Looking forward to your two answers for the 29th time.
=========================
Note. The values of V2 and V3 depend on the value of N as well as on the zigzags shapes (curve patterns).

[George1]

Don't be afraid of truth!
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Asking my two simple questions for the 30th time.
--------------------------------------------
1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
--------------------------------------------
2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;   
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
3) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum will be correct and (b) the law of conservation of mechanical energy will be incorrect. 
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4) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum will be incorrect and (b) the law of conservation of mechanical energy will be correct. 
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5) Or may be both (a) the law of conservation of linear momentum and (b) the law of conservation of mechanical energy are actually incorrect simultaneously in this special particular zigzag case?
--------------------------------------------
So let us ask again our two simple questions for the 30th time.
--------------------------------------------
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
--------------------------------------------
Looking forward to your two answers for the 30th time.
--------------------------------------------
Don't be afraid of truth!

[George1]

Let us work together and not to confront!
Let us push forward together the technology progress!
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Asking my two simple questions for the 31st time.
--------------------------------------------
1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
--------------------------------------------
2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;   
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
3) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum will be correct and (b) the law of conservation of mechanical energy will be incorrect.
--------------------------------------------
4) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum will be incorrect and (b) the law of conservation of mechanical energy will be correct.
--------------------------------------------
5) Or may be both (a) the law of conservation of linear momentum and (b) the law of conservation of mechanical energy are actually incorrect simultaneously in this special particular zigzag case?
--------------------------------------------
So let us ask again our two simple questions for the 31st time.
--------------------------------------------
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
--------------------------------------------
Looking forward to your two answers for the 31st time.
--------------------------------------------
Let us work together and not to confront!
Let us push forward together the technology progress!