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Overunity Machines Forum



IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?

Started by George1, July 21, 2018, 08:11:37 AM

Previous topic - Next topic

0 Members and 1 Guest are viewing this topic.

George1

To Jerry Volland.
==========================
Your masters will beat you for sure! You have to hide in the Afghan mountains! You have to run quickly! :)
==========================
I am asking (YOU PERSONALLY!) my simple question for the 50th time.
--------------------------------------------
1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
--------------------------------------------
2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;   
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
3) It is evident that (always) V2 > 0 m/s and V3 > 0 m/s.
--------------------------------------------
4) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum is valid and (b) the law of conservation of mechanical energy is invalid.
--------------------------------------------
5) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum is invalid and (b) the law of conservation of mechanical energy is valid.
--------------------------------------------
6) It is evident that if (a) V2 is not equal to 0.6 m/s, and if (b) V2 is not equal to 0.8 m/s, and if (c) V3 is not equal to 0.1 m/s, and if (d) V3 is not equal to 0.3 m/s, then both (e) the law of conservation of linear momentum and (f) the law of conservation of mechanical energy are invalid simultaneously in this special particular zigzag case, which is described in the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
--------------------------------------------
I am asking (YOU PERSONALLY!) my simple question for the 50th time.
--------------------------------------------
QUESTION: Do you have any objections against any of the above items 3-6? Yes or no? (And if yes, then specify exactly which item you do not agree with and why.)
--------------------------------------------
Looking forward to your (PERSONAL!) answer for the 50th time. (Only one word -- either "yes" or "no"!)


George1

To Jerry Volland.
=====================
Where are you sending your posts from? From the Afghan mountains? :) Or from the Brazilian jungle? :) Hope that your hiding place is reliable, because your masters will not forgive you your constant failure to manipulate successfully the audience.
=====================
I am asking (YOU PERSONALLY!) my simple question for the 51st time.
--------------------------------------------
1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
--------------------------------------------
2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;   
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
3) It is evident that (always) V2 > 0 m/s and V3 > 0 m/s.
--------------------------------------------
4) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum is valid and (b) the law of conservation of mechanical energy is invalid.
--------------------------------------------
5) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum is invalid and (b) the law of conservation of mechanical energy is valid.
--------------------------------------------
6) It is evident that if (a) V2 is not equal to 0.6 m/s, and if (b) V2 is not equal to 0.8 m/s, and if (c) V3 is not equal to 0.1 m/s, and if (d) V3 is not equal to 0.3 m/s, then both (e) the law of conservation of linear momentum and (f) the law of conservation of mechanical energy are invalid simultaneously in this special particular zigzag case, which is described in the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
--------------------------------------------
I am asking (YOU PERSONALLY!) my simple question for the 51st time.
--------------------------------------------
QUESTION: Do you have any objections against any of the above items 3-6? Yes or no?
--------------------------------------------
Looking forward to your (PERSONAL!) answer for the 51st time. (Only one word -- either "yes" or "no"!)
=========================
SIMPLY ANSWER MY QUESTION BY USING ONLY ONE WORD -- EITHER "YES" OR "NO"! 
 

George1

To Jerry Volland.
======================
You have specified nothing! You have never specified anything! All of your objections/posts/comments/opinions, related to our zigzag principle, have always been unskillful manipulation tricks with no connection to the topic discussed. And this is evident for all honest members of this forum. Can't you understand that with your absurd stubbornness you resemble already a clumsy clown? :)
======================
I am asking (YOU PERSONALLY!) my simple question for the 52nd time.
--------------------------------------------
1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
--------------------------------------------
2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;   
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
3) It is evident that (always) V2 > 0 m/s and V3 > 0 m/s.
--------------------------------------------
4) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum is valid and (b) the law of conservation of mechanical energy is invalid.
--------------------------------------------
5) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum is invalid and (b) the law of conservation of mechanical energy is valid.
--------------------------------------------
6) It is evident that if (a) V2 is not equal to 0.6 m/s, and if (b) V2 is not equal to 0.8 m/s, and if (c) V3 is not equal to 0.1 m/s, and if (d) V3 is not equal to 0.3 m/s, then both (e) the law of conservation of linear momentum and (f) the law of conservation of mechanical energy are invalid simultaneously in this special particular zigzag case, which is described in the link https://www.youtube.com/watch?v=xX14NK8GrDY  .
--------------------------------------------
I am asking (YOU PERSONALLY!) my simple question for the 52nd time.
--------------------------------------------
QUESTION: Do you have any objections against any of the above items 3-6? Yes or no?
--------------------------------------------
Looking forward to your (PERSONAL!) answer for the 52nd time. (Only one word -- either "yes" or "no"!)


ramset

Mr Jerry
As a known person using your Sir name ( as I also do on this and other forums ( my profile since day one)
What is taking place here _against you_ from an "anonymous person/poster


constitutes a violation of law and forum terms of service agreement!


??





Whats for yah ne're go bye yah
Thanks Grandma

ramset

FE Researchers ,


After many attempts by members to help here


None resulted in anything except flames and insults and spam !


Stefan has removed much spam and  placed moderation ( both topics)


Respectfully
Chet K
Edit for clarity (removed Gentlemen and replaced with "FE researchers"
Not all are Gentlemen here ...?!)
Whats for yah ne're go bye yah
Thanks Grandma