Zero and Q device

[lancaIV]

Volt Ampere,

https://en.m.wikipedia.org/wiki/Volt-ampere_reactive
https://en.m.wikipedia.org/wiki/Ampere-turn

[Void]

My explanation for the operation of the 'Zero' circuit: -

Using my 25W bulb having a cold resistance of 204R, the bulb in series with a 10uf cap and diode, the bulb does not visibly flash on connection to a 240V mains supply. However, it will flash with a 20uf or higher value cap. The difference is due to the reactance of the capacitor allowing sufficient current to heat the bulb filament to a glow in the case of the 10uf cap. The combined series capacitance of C1 to C4 in the zero circuit is around 5uf, thus no flash.

When the transistor is switched 'ON' and conducts on one phase of the mains supply, caps 1 to 3 effectively discharge in parallel to a much lower resistance output circuit, via steering diodes, to common output rails to which L2 is connected. The combined currents through the lower resistance, discharged from caps 1 to 3 are sufficient to heat the filament of L2. However, L1 cannot light on this phase as the diodes in series with the caps are reverse biased. The caps are now discharged ready for re-charge on the next phase when the transistor is switched 'OFF'.

Altering the power rating of the bulbs and cap values will alter the impedance of the input loop to an extent whereby LI may be seen to glow together with L2.

Hi Hoppy. Sounds right to me.
All the best...

[Void]

If voltage on L1 is so low, try to grab L1 with your hand.
Everything will be clear to you in split second.
L1 is directly on mains 220V.
But it can not push lot of current through bulb.
And in the second phase voltage is double on that line.

Hi v8karlo. I did not say the voltage 'on' L1, I said the voltage *across* L1, i.e. the average voltage drop across L1.
Just because you don't understand the basics of electric circuits very well, it doesn't mean other people don't or can't
understand the circuit well, even just by looking at the schematic. 

Carroll's and Hoppy's analysis seems to be correct to me. The caps charge up from the mains through L1 in one half
of the AC cycle. Since the caps and L1 are in series, the voltage from the mains will divide across them.
There is not enough average voltage drop across L1 to light it up brightly, even though current is passing through it
to charge the caps which are in series. In the second half of the AC cycle, the caps (in parallel) discharge through L2
and light it up. Given this analysis, there is no reason at all that I can see to think this circuit arrangement might be 'free energy'.
You are just charging up caps from the mains in one half of the AC cycle and discharging those caps through L2
in the second half of the AC cycle. Sorry mate. It appears there is no magic to find there. This is not surprising at all since
IMO any given setup would have to draw in extra energy from outside the circuit to be able to achieve COP >1.
I hope this is beginning to sink in now, but I won't hold my breath waiting for that moment to happen. 
All the best...

[v8karlo]

Sorry mate. It appears there is no magic to find there.

I know what you mean by voltage drop across element.

So, how you explain extra light and heat on output while input is cold and without light?
Hoopy didn't explained that, neither do you. He did not explain 175V on each cap?
Do you have your explanation of extra light and heat?


Try to remove CZero and plug it that way.
You will see how magic vanish and there is no 175V on caps.
Try that.

Power on output will be the same or less than input now.
Why is that?

You did not change anything else.
Your circuit stays the same,
you still have your voltage divider,
but the power from caps is gone now.

Something is not right here, does it?

Now you have ordinary, simple useless circuit.
More input than output.

[v8karlo]

At the end, maybe CZero is doing what it is supposed to do?
Raise the voltage on the caps.

With voltage the power in caps is also raised.
And the power on output is going up.

What you think about that?

Magic? I don't think so.

Some things are very hard to accept. Obviously.