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Overunity Machines Forum



Zero and Q device

Started by v8karlo, January 04, 2019, 11:18:12 PM

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0 Members and 21 Guests are viewing this topic.

v8karlo


I received 11 confirmation of successful replications of Zero device till now.

People also confirming that Zero device is true overunity device.


Once more, Zero device has 3 variable:
1. Input grid voltage
2. Number of capacitors (in series)
3. Resistance of load, output (L2 bulb)

Capacitors have resistance, it is not linear.
Number of capacitors multiplies current by 1 with every new cap added.
Output voltage do not drop lineary with every cap added in series.

v8karlo


People are also complaining that they do not want to post here because of the attacks from individuals on this forum.

They prefer to contact me by mail which is more complicated because of the number of mails received every day.
Do not be afraid! Post here whatever you want. It is easier that way.


The attackers are few. You are many.

v8karlo

Quote from: v8karlo on January 11, 2019, 03:55:39 AM

Output voltage do not drop lineary with every cap added in series.


Hi, I will answer your question from mail here. I had similar question before.

What is difference in a number of capacitors in Zero device?

There is non linearity there. It is not obvious. It is kind of hidden.
Let's say that the source current is 1A. With 3 caps in series they will produce 3 x 1A = 3A. With the help of Czero cap the voltage will raise to 525V. (input voltage is AC 220V, Europe)

So 525V / 3 caps = 175V on each cap (C1, C2, C3). So 175V is output voltage.

Now, if we add 1 cap more in series we will have 4 caps in series. They will produce 4A. And the voltage on each will be 525V / 4 = 131V on each cap. Difference in voltage is from 175V to 131V = 44V.

If you add 9 caps they will produce 9A and voltage on each cap will be 525V / 9 caps = 58V.
If you add 10 caps they will produce 10A and voltage on each cap will be 525V / 10 caps = 52V.
Difference of output voltage between 9 and 10 caps in series 58V – 52V = 6V.

Difference between 3 and 4 caps in series is 44V (on output).
Difference between 9 and 10 caps in series is 6V (on output).

See difference here (44V and 6V).

That means that with each cap added you gain 1A and after number of caps the output voltage drops only for little.

That means that you have to raise input voltage only for a little and you gain always 1A with every cap.
Of course, capacitors have resistance and in reality they will behave little bit different (like resistors 5-10ohm).
This is only explanation of relation between number of caps and input, output voltage.

After a 20 caps in series you have to raise input voltage only for the fraction to raise output voltage on that caps but with every cap added you gaining always 1A. It is serial connection law.

What about after 60 or 200 caps? You have to raise input voltage only for 1V or less to gain 1A.

I hope I helped.

v8karlo


Another one from mail.

"Can I use battery on output instead of bulb?"

This is little bit tricky, but not hard.
If you only wanna to fill battery to 12V it is not a problem.

But if you wanna fill battery and in the same time use battery for some load??
First, 525V / 12V = 43. You have to put 43 capacitors in series to adjust output little bit over 12V and multiply current. (or just 40 caps).
This can be trial and error because caps have resistance, so the number of caps can not be determined only by calculations.
The output from battery has to be in opposite phase than output of Zero circuit.
The battery which contains some voltage is resistance for output of Zero.
If current just pass over the battery to load you don't have any resistance.

(If the load is low resistance, and most of the time at 12V the load is low resistance)

And the device needs resistance on output. Capacitors should never empty all the way.
So the process has to go in opposite phases.
Fill the battery from Zero. Stop. Use energy from battery. Stop.
Sequencing!

And the battery should always have some level of voltage in it.

I tried this with 18 capacitors and with small 12V, 1.2Ah battery.
But I didn't used grid at that experiment.
I was raising voltage via push pull small transformer from same battery.

At the beginning my idea was to make PC power supply which is energy efficient.
With Zero circuit grid does not have any influence on output (spikes or any RF or trash from grid, or overvoltage from grid).
When you stop spending on output, Zero circuit automatically stops, and spends nothing.Caps are full and it just stops.

NickZ

   V8Karlo:   The higher that the voltage is raised, the lower will be the amperage at the output. You are mentioning about input voltage to output voltage, but that does not mean that there is more usable power at the output.
   Raising the voltage is easy, but that does not give you more total power. If you think that it does, you should be able to light more than just a small bulb.
   There are no attacks here. There are questions to be answered. And videos demonstrating the device with some actual readings are needed to back up the claims which up to now have not shown OU, nor self running.
   As this is a free energy forum, the goal is not to light bulbs from the grid, nor to drain batteries like a regular inverter would do, but to show something unusual.   What is unusual about this device?