A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1

[George1]

The text below is a slightly modified, shortened and more precise version of our post of March 09, 2021, 02:46:35 PM.
----------------------------
Have a look again at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)
The same book can be found at the link https://books.google.bg/books?id=rrKFzLB9KQ8C&pg=PA876&lpg=PA876&dq=%22electrochemical+equivalent+of+hydrogen%22&source=bl&ots=tQ8PSMLet3&sig=ACfU3U2HOLB78XHl2o3q-JanapzSK-McJA&hl=bg&sa=X&ved=2ahUKEwjDpp2-zZXhAhWT5OAKHUfuBzUQ6AEwBHoECAkQAQ#v=onepage&q=%22electrochemical%20equivalent%20of%20hydrogen%22&f=false
--------------------------
For your convenience I am giving below the text of the problem and its solution.
--------------------------
12.97. In the electrolysis of sulphuric acid solution, 100 mg of hydrogen is liberated in a period of 20 minutes. The resistance of the electrolyte is 0.5 Ohm. Calculate the power consumed. Electrochemical equivalent of hydrogen is 1.044 x 10 -8 kg/C.
SOLUTION.
Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------
Prof. S. L. Srivastava stops here his calculations.
(The related solution's set of equations is not given here in order to save time and space. This set of equations however can be found in the book or in the link above.)
--------------------------
WE DEVELOPED FURTHER PROF. SRIVASTAVA'S SOLVED PROBLEM IN A NON-STANDARD MANNER.
OUR FURTHER DEVELOPMENT OF PROF. SRIVASTAVA'S SOLVED PROBLEM LED TO COP > 1.
HERE IS THE ESSENCE OF OUR APPROACH.
--------------------------
1) Let us calculate the inlet energy, that is, inlet energy = (31.86 W) x (1200 s) = 38232 Ws = 38232 J.
2) The Joule's heat, generated in the process of electrolysis is given by
Q = (I) x (I) x (R) x (t) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) x (t) = (31.86 W) x (1200 s) = 38232 Ws = 38232 J = outlet energy 1.
3) HHV of hydrogen is 142 000 000 J/kg. Therefore the heat H, generated by burning/exploding of 0.0001 kg of hydrogen, is given by
H = (HHV) x (m) = (142 000 000) x (0.0001) = 14200 J = outlet energy 2,
where
m = mass of the released hydrogen
HHV = higher heating value oh hydrogen
4) Therefore we can write down the equalities:
4A) outlet energy 1 + outlet energy 2 = 38232 J + 14200 J = 52432 J
4B) inlet energy = 38232 J.
5) Therefore COP is given by
COP = 52432 J/38232 J = 1.37 <=> COP = 1.37 <=> COP > 1.
------------------------------
IMPORTANT NOTE. Constant pure water and cooling agent supply could keep constant the electrolyte's temperature, heat exchange, mass and ohmic resistance, respectively. Besides 0.0001 kg of hydrogen (and the related amount of the already split pure water) is small enough and can be neglected as a factor influencing the electrolyte's temperature, mass and ohmic resisitance.
-----------------------------
And one more interesting fact.
Literally the same solved problem can be found in an old Russian (still from the Soviet times) book "Сборник задач и вопросов по физике", 1986, p. 130, solved example problem 71. The authors of this book are Р. А. Гладкова and Н. И. Кутиловская. In the Russian version the data is a little different, that is, time is 25 minutes, the amount of generated hydrogen is 150 mg, Ohmic resisitance is 0.4 Ohm and the calculated power is 37 W.
Russians also stopped their calculations at 37 W.
Our further development of the Russian version led to the same COP = 1.37, that is, we have again the same COP > 1.

[George1]

EXPERIMENTALLY PROVED reactionless drive and perpetual motion are described in the link below:
https://www.youtube.com/watch?v=xX14NK8GrDY&ab_channel=PeterAxe
The link above describes a few simple reactionless drive and perpetual motion experiments. You can easily carry out these simple experiments in your garage as many times as you want.
Looking forward to your comments.

[George1]

Still no comments related to the link below?
https://www.youtube.com/watch?v=xX14NK8GrDY&ab_channel=PeterAxe
--------------------------
What happens here? Where is the new technologies pioneer spirit here in this forum?
--------------------------
Looking forward to your answers/comments.

[kolbacict]

Here's who has excess heat ...
https://www.academia.edu/19925139/Ultrasonically_excited_electrolysis_Experiments_at_Energetics_Technologies?email_work_card=view-paper

[ramset]

Hello
I have built the sand heating. But still problems with the setback. Catalyst is from the Mercedes w124. After a few minutes, it ignites automatically. The temperature in the catalyst rises very quickly. I will try to grind the catalyst and mix it with sand.
greeting
Lota

lota
Here a quick vid/explanation of what Acca is using , and how to harvest it


I suppose as we proceed ( I will also be building ) we can share process for smashing and mixing into sand
Years ago a YouTube group "waterforfuel " ( or something like that ) had shared some vids on HHO and catalytic reaction , at that time I thought some had analyzed the process for energy audit _power used to heat production _ efficiency...


There is remarkably simple caloric test method to prove this now !


I will be building smallest most efficient Hho cell possible for testing as time permits


https://m.youtube.com/watch?v=_u3WfZa_9ko


Here vid showing where material comes from (go from to 1-2 minute mark , rest of vid is process for harvesting platinum and noble
Metals


Thx
Chet
Ps to OP (original poster George) here
This is not typical to assume you are ok with this discussion in your topic
However seems to be tolerated?


Are you OK with this discussion here?


I will be starting separate topic at other open source forums if this proves viable
(And also here.. separate teaching section)


?