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Cadman’s Hydrostatic Displacement Engine

Started by Cadman, June 15, 2019, 05:14:21 PM

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Cadman

5" for 1:8 scale. The 125 g is according to my figures trying to scale the piston weight so the psi under the piston would be scaled.

I think my figures are right but would appreciate a confirmation. My head is quite foggy today.

Respectfully
Cadman

Grumage

Post script.

Aren't we forgetting about the fact that the displacer piston is attached to the power piston assembly?

Wasn't the figure of 20 Lbs mentioned?

Cheers Graham.

Cadman

In the analysis I posted, 17 lbs included the whole assembly.
If you want to use 20 lbs, that's OK at this point.
Maybe that's what it needs to be. It's a work in progress.

Cheers
Cadman

PS. We want to use the lightest piston assembly that will do the job. The lighter it is, the more power we'll have on the up stroke.

Floor

Just an Idea, as an aside, not to distract from the good progress.

In the drawing the fluid is flowing down from the reservoir  to the power piston
it would then lift the displacement piston represented as the weight.  Don't know how
it would then reverse.

tinman

Quote from: lumen on June 26, 2019, 12:21:33 PM
The answer is very simple. The displacer is exactly what it must do (in this case ) displace water.
In the vertical position it will sink (displace water) only until the water it displaces equals the weight of the displacer.

Not hard to understand.
To displace water for the entire length of the displacer would require it to weight as much as it's exact volume in water.
If it does not, it will sink only to a point where the water it displaces is equal in weight to the displacer.

I think this will be a problem unless it can be done in an additional step just to raise the displacer.

That is not correct.

Here we are dealing with hydraulic pressures and forces,not buoyancy forces.


Brad