Power from repelling magnets

[ayeaye]

I have not processed my mu metal anyhow, i use it as it is, and when i tried it with smaller magnets, it seems to work. How to heat treat it to restore its properties after cutting? Mu metal seems to be like a soft iron what concerns cutting and such.

To measure forces, one may use this dynamometer or Newton meter, $2.80, 1 N, should be enough for small magnets.  https://www.ebay.com/itm/Newton-Meter-Force-Meter-Spring-Dynamometer-Spring-Dual-Scaled-Balance-1N-25N/383050856492?hash=item592f9c382c:m:m11m1P8VDNANPV-qUbiI0SQ  That's like fish scales, hanging scales, but much cheaper. This supposed to have a precision 0.01 N, that's precise enough. Don't know how precise it really is, but it's certainly more precise than fish scales, and at least at first likely precise enough. Certainly much much better than not measuring forces at all.

[ayeaye]

I bought both 1N and 25N dynamometers, these  https://www.ebay.com/itm/1N-25N-Newton-Meter-Force-Meter-Spring-Dynamometer-Spring-Dual-Scaled-Balance/362700884452?hash=item5472a849e4:m:m11m1P8VDNANPV-qUbiI0SQ , should arrive on January 1. I think this is enough to measure all kind of forces. I will tell you more about them when they arrive, i don't think it would be a great harm though to buy them now. I have seen that a spring Newton meter is very accurate.

In Amazon one can find these when searching for "spring scale". I think they should be called "Newton meter".

[ayeaye]

I don't know, the mu metal on that drawing, what mu metal supposed to do, is that it takes field lines inside itself. They likely go out from the edge, there they are not reduced but, as the edge is quite narrow, the vertical vector component of the negative attraction there should become quite short (because it is bent by the shield to be perpendicular to the direction of movement). An iron shielding supposed to do the same, and maybe it would be sufficient, but the iron shielding has to be thicker, and this would make the vertical component of the negative attraction longer.

Perhaps the screw has to be on a disk, providing only an approximation of a linear movement, may be enough. I have used computer fans with a cd (dvd) disk on it. Hard drives have very good ball bearings, but some say that they don't tolerate much horizontal forces.

I got a mu metal from an old hard drive. The magnet there also fits to the experiment, it has poles on both ends, and mu metal then has to be on it perpendicularly, it's a bit awkward, but may work. The mu metal there is in two flat pieces. I had to bend it a bit, to get it out, i don't know whether that decreased its properties. But it seems to shield well with small magnets. Otherwise, i didn't process it, just put it as it is, on the pole of the magnet.

Like the screw there, first it is attracted positively, positive attraction is in the direction where it supposed to move. Then there is negative attraction, opposite to that direction. The overunity in that is the energy of positive attraction (positive energy), minus the energy of negative attraction (negative energy). Friction should be measured separately. Then for theoretical overunity calculation, the friction energy of the positive phase (the distance moved under positive attraction) should be added to the positive energy, and the friction energy of the negative phase (negative phase friction) should be subtracted from the negative energy. Then the negative energy so calculated, should be subtracted from the positive energy so calculated.

Well the friction, this of course is more complicated. Maybe it can be assumed that like in the case of a computer fan, the radial forces don't increase friction sufficiently. Otherwise, the force attracting the stator magnet towards the disk, should be somehow measured, like maybe turning the stator magnet 90 degrees, and measuring force to the screw. Then knowing that force, we may take the simplest case. Turn the disk vertical, and hang something with that weight to it. Measure force moving a certain distance, this multiplied by the distance is all energy, and by how much it lifted the weight, is the energy in addition to friction, subtract that from all energy, and from that calculate the friction force. Something, i cannot say exactly how to do everything, as it depends on the particular case, may be simpler, may be not.

I think it can be assumed that the friction force is present even when measuring forces statically. Like when the friction is very high, the force we measure is zero, because all force goes to friction. Please correct me if you think it's different.

I don't know about that thing more, how well it works. I just wrote everything i know, so may be useful for someone. I'm unlikely to do experiments. Most important is that asymmetry of the magnetic field, this seems to be quite certain. And important is to know that there may be overunity, even if it cannot overcome friction.

[kolbacict]

Why am I failing?
https://www.youtube.com/watch?v=NuwNxfs5ocE

[ayeaye]

Why am I failing?
https://www.youtube.com/watch?v=NuwNxfs5ocE

I explained you, V-gate has no overunity. It is basically just magnets coming closer, and it ends when they don't come more closer and start from the beginning. For continuous overunity one has to use the asymmetry of the field, as also described above. Rather learn that.

V-gate doesn't use the asymmetry of the field, and this means that the output energy cannot be greater than the input energy. No matter what mechanism to use to gather energy, and then use it again, to move from the end to the beginning again, it just cannot work.