Centrifugal guns...

[sm0ky2]

http://en.m.wikipedia.org/wiki/Centrifugal_gun


Hmm

[tinu]

https://www.youtube.com/watch?v=w-7d66JscI8

In the 1.320 kg model the original energy is about .66 joules.

The final energy of the .132 kg moving ten times as fast is 6.6 joules.

That is a production of 5.94 joules.

The final energy of the .132 kg balls in the free-falling frame of reference is also about .66J.
The balls does not move ten time as fast. They simply move with constant velocity, while initially unwinding the wire then winding it back.There are no forces to accelerate the balls, hence their speed remain constant.

[Delburt Phend]

The spheres are only one tenth the origin quantity of rotational motion. The total mass is 1320 grams and the spheres only have a mass of 132 grams.

The spheres have all the rotational motion when the cylinder is stopped.

Ballistic pendulums prove that only linear Newtonian momentum can be given from a small mass to a large mass.  Energy is not conserved in the motion.

The spheres are smaller masses and they have all the motion and they return all the rotational motion back to the cylinder.

The only thing that can be happening is that the spheres receive all the linear Newtonian momentum and then they give it back again.

I use slow motion and go frame by frame; and all the rotational motion is returned to the cylinder after  the cylinder has been stopped.  Only Newton's momentum can do this. The spheres are moving 10 times faster when they have all the motion.

[Delburt Phend]

There are forces acting within the closed system. (132 g / 1320 g)

The original motion of the 1188 (1188g + 132g = 1320g) gram cylinder is about one meter per second. In a short period of time (around .1 second) the cylinder's rotation has stopped. This stop requires the application of 11.88 newtons of force; applied for .1 seconds. This force is applied by the tension in the string; and the force is applied equally to the cylinder and to the spheres. (Third Law)

When you apply 11.88 newtons of forces to a .132 kg mass for .1 seconds you will get a velocity change of 9 m/sec.        F = ma and V = at

Like the cylinder: the original velocity of the spheres was one meter per second; when the additional 9 m/sec is added we have 10 m/sec.

After the cylinder has stopped: and the strings and spheres are left attached the 11.88 newtons kicks in again and it reverses the process. The cylinder is accelerated up to one m/sec and the spheres slow back down to one meter per second. This 11.88 newtons is of course the average force. And even to my surprise; the spheres do not crash into the cylinder. They simply fly in formation just above its surface.

[tinu]

There are forces acting within the closed system. (132 g / 1320 g)

The original motion of the 1188 (1188g + 132g = 1320g) gram cylinder is about one meter per second. In a short period of time (around .1 second) the cylinder's rotation has stopped. This stop requires the application of 11.88 newtons of force; applied for .1 seconds. This force is applied by the tension in the string; and the force is applied equally to the cylinder and to the spheres. (Third Law)

When you apply 11.88 newtons of forces to a .132 kg mass for .1 seconds you will get a velocity change of 9 m/sec.        F = ma and V = at

Like the cylinder: the original velocity of the spheres was one meter per second; when the additional 9 m/sec is added we have 10 m/sec.

After the cylinder has stopped: and the strings and spheres are left attached the 11.88 newtons kicks in again and it reverses the process. The cylinder is accelerated up to one m/sec and the spheres slow back down to one meter per second. This 11.88 newtons is of course the average force. And even to my surprise; the spheres do not crash into the cylinder. They simply fly in formation just above its surface.

Indeed, you're right. My bad.Still, the energy is being transferred from the cylinder to the balls.The movie ends to soon to tell but so far I can not see that more energy is transferred back from the balls to the cylinder.Maybe you can shed some light on this issue?Best regards!