Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Help me understand complementary push pull amp

Started by nix85, March 09, 2021, 05:29:27 AM

Previous topic - Next topic

0 Members and 1 Guest are viewing this topic.

nix85

I got trouble understanding how EXACTLY you imagine half bridge creating AC.

(Let's ignore the fact that you cannot just recreate the missing halfcycle and call it HiFi)

Now you are mentioning resonance and inductors.

Let's first get some basics out of the way...


We all know no electrons pass through a cap, but a changing electric field, displacement current..

We also know reactance of the cap is XC= -1/2πfC

So, higher the frequency and capacitance, more it looks as if cap is not there.

We also know in purely capacitive or inductive circuit voltage and current are 90° out of phase.

Any changing waveform passes "through" a cap, be it pulsed DC or AC.

So halfsinewave passes through a cap as easily as a whole sinewave does.

In other words, when the halfsine ends, with slight delay, voltage would pass through the cap leaving it uncharged.

So let's bring in resonance. If we are talking LC tank instead of a cap alone, then it depends if it's in series of parallel.

Series LC tank at resonance is short circuit, in parallel open circuit..

So, how exactly is other half of the sinewave produced.


AlienGrey

It sounds like you dont experiment  a capacitor is an insulator so how can it pass currevt ?
it charges and discharges it's size demnds on its time and frequency and how it's charged

Also if the cap is in series your DC content is lost.

Also if you bias a semiconducter on its on off slope your moving its DC swing in your circuit.

nix85

Quote from: AlienGrey on March 10, 2021, 04:28:06 AM
It sounds like you dont experiment  a capacitor is an insulator so how can it pass currevt ?
it charges and discharges it's size demnds on its time and frequency and how it's charged

Also if the cap is in series your DC content is lost.

Also if you bias a semiconducter on its on off slope your moving its DC swing in your circuit.

I do experiment and build but you clearly don't know the basics.

You don't know what displacement current aka capacitor current is, google it.

"Wire has inductance" sooo? Unless it's coiled inductance is negligible.

Everything i wrote is COMMON ELECTRONIC KNOWLEDGE.

Everything you crossed and called wrong is correct.

"It depends on slope bias set up", no it doesn't, you can't recreate the missing halfcycle and call it HiFi.

All changing voltage waveforms indeed pass through a cap, be it pulsed DC or AC... even pulsed DC squarewave signal will pass through a cap at the moment of the change.

Back to school.


antijon

The first image that you posted wouldn't work. As it is nothing would happen on the neg half cycle.

Just saying it's more likely that they forgot to add the label for -VCC at the bottom rail.

Otherwise, you could replace the "ground" at the load with the center tap of a voltage divider. e.g. if you had 12V from VCC rail to bottom rail, when the top transistor closes the load would see 6V+ from VCC to center tap. When the bottom transistor closes the load would see 6V- from center tap to bottom rail. (Don't really know if this would work because I don't do electronics but it seems feasible in my head lol)

nix85

They did not forget it is implied and most often symbolized that bottom is also "ground", that is, Vcc-.

Of course "ground" does not always have to be Vcc-, it's just a circuit wide reference point.

Here is the first diagram on google images for push pull amp

Looking at these diagrams one would conclude that during negative halfcycle current flows from ground to ground, lol.