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Help me understand complementary push pull amp

Started by nix85, March 09, 2021, 05:29:27 AM

Previous topic - Next topic

0 Members and 4 Guests are viewing this topic.

nix85

This guy is "explaining" it and of course does not address the issue.

https://www.youtube.com/watch?v=2lqwA3lkTT8&t=449s

People in comments noticed.

And then we wonder why ppl don't understand shit. Almost nothing is explained right.

AlienGrey

If you understand sh would that be a hallo of some sort ? ;D ;D

If you conect the lower transister to a -12 Volts it will go bang !

Do you know why ?

antijon

AlienGrey, is that why they sometimes put a capacitor before the input? I don't know about with a square wave, but a sine would pass through the cap. and show a pos. and neg. value.

Nix, I can see why that would work in the video, at least the diagram with the capacitor before the output load. The cap. charges during the pos. half wave, and negative half wave discharges the cap. through the bottom transistor. The load after the cap. should see a forward and reverse current

nix85

Quote from: antijon on March 10, 2021, 05:45:49 PM
Nix, I can see why that would work in the video, at least the diagram with the capacitor before the output load. The cap. charges during the pos. half wave, and negative half wave discharges the cap. through the bottom transistor. The load after the cap. should see a forward and reverse current

Capacitor before the input is to remove any dc.

Yea, that's what i assumed too. Keep in mind

all changing voltage will pass through the cap.

Only the dc bias 1/2 Vcc can remain on it to

discharge in opposite direction.

nix85

Quote from: AlienGrey on March 10, 2021, 04:05:18 PM
If you understand sh would that be a hallo of some sort ? ;D ;D

If you conect the lower transister to a -12 Volts it will go bang !

Do you know why ?

LOL i see you are still confused,
have you at least learned what displacement current is
and that all changing signals pass through a cap ? ;D ;D