Milkovic's Pendulum

[Johnsmith]

Why is oil still not pumped using help of Milkovich's double pendulum?

  It might be interesting if they tried it. With your Maxwell pendulum, is the line securely attached?
You might need to use a screw or drill a hole through the rod that you're using. Also your weight
has to be secured to the rod.

[Johnsmith]

Hello John,
I'm finishing this week a proto that I believe in a lot, which uses a principle not far from yours, but simpler, it's about mounting a weight.
It is in the organization of the weights that we are very different.
I can't show you anything at the moment, but at the end of the week we will know. I am associated in the idea with a member that you probably know is Robinhood46.
If my proto falls through you can count on me.


A++

  Bon chance.

[Johnsmith]

 thx4 and Robinhood46, some numbers for you guys to consider. This is with the counterweight
and the fulcrum for the pendulum both 50 cm from the fulcrum for the crossbar using a .5kg weight.
If the counterweight drops 5 cm then the fulcrum for the crossbar rotates 11.5°. How work would
be transferred. If the swinging weight is inward at a 45° and it is 50 cm from its fulcrum, the
counterweight will need to drop 3 cm to lift the pendulum. This is by calculating work. The pendulum
would be 15 cm from the fulcrum of the crossbar. It's mass would be factored as 30° of the counterweight.
This leaves 7 cm of drop for the counterweight. For the swinging pendulum to be rotated upwards
at a 1:1 ratio, the counterweight couldn't lift it. And this is where if the counterweight rotates it 2
to 3 cm then the ratio becomes 7:2 or 7:3. That is where free energy could be realized.
This is an example of the math. It could be converted into n-m if you guys are familiar with doing that.
I already have a unique design for the gears that control the pendulum because it needs to be caught
then released.
This is where when you guys would like to discuss this further just let me know. Then it can be diagrammed
in a way that you readily understand it. Also, the counterweight would be heavier because as we all know, a
swinging pendulum has inertia which is in addition to gravity.

p.s., I think you guys know the real work starts when you have to work out the mechanics and the details so it will work.

[Floor]

Couple of basic questions.


1. Do pendulums remain in motion longer than do balanced spinning wheels ?

2. Do balanced spinning wheels remain in motion longer than do
unbalanced spinning wheels ?

[Johnsmith]

Couple of basic questions.


1. Do pendulums remain in motion longer than do balanced spinning wheels ?

2. Do balanced spinning wheels remain in motion longer than do
unbalanced spinning wheels ?

  And yet you don't understand that inertia increases the work that a swinging pendulum can do?
Myself I think it would be pretty cool to see a perpetual pendulum working. Then it would be a
counterbalanced pendulum that has a single oscillation.
Hopefully you're aware that when a swinging pendulum is moving downward it is moving in the
direction of gravity and not perpendicular to it? This is why mv^2/r increases it's force.
If a pendulum were spinning around a tether ball pole then it would have inertia but no influence
from gravity. This is where the basic math is g * sinx + i = f. See how easy that is? And with a
tether ball orbiting its pole it is i = mv^2/r = f.
This is why a swinging pendulum can lift a heavier counterweight. And that creates a source of free energy.
And I would like to apologize to you but I am not a math tutor. Maybe you could Google one?

p.s., i in the equations I stated is mv^2/r or mass * velocity squared divided by the radius. And g = gravity
gives a 1 kg weight 9.81 newton's of mass. If it's not moving then it has no force because force = mass * acceleration
which is mass * d/t (distance divided by time). Kind of why m/s is used.
And with sinx it is sine times the variable x which is the angle in degrees relative to its axis of rotation.