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Overunity Machines Forum



Holcomb Energy Systems:Breakthrough technology to the world

Started by ramset, March 14, 2022, 11:07:24 AM

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0 Members and 33 Guests are viewing this topic.

floodrod

What I have learned with my Choke Experimentation is that inductors "induct" back into themselves with every turn.  Even without a rotor- the quicker you pulse a coil, the more back-EMF it sends from itself.

The quicker you change flux fields in an inductor, the more back EMF it sends. Hence why driving amperage goes way down as you pulse quicker. So it's a catch 22.  Pulse too quick and you can't push decent amperage through the coil anymore so the very act of creating that Back EMF diminishes because the coil itself needs amperage to induct and create Back-EMF.

The formula not only depends on number of turns and wire gauge, but also frequency and how much of the flux you allow to escape.  Enclose that coil in a full core so no flux escapes, and back EMF goes to almost 100% and driving amperage goes to practically nothing.

Ohm's law can not be used alone on an inductor with switching polarities. I do not know the exact formula, but I know for 100% certain if I send AC into an air coil, I can read higher voltage and amperage on the air coil than I am sending in.  Add an enclosed core, and with the use of diodes or tiracs, that back EMF becomes able to be separated and used on loads.

Measuring from source + terminal to ground, you may be sending in 10 volts. Separate + source terminal and the inductor with a diode or triac, and if you tune it right, you can get more than +20 V from the circuit side of the diode to ground. More than 2X terminal voltage.  And this voltage is real. You can run loads backwards to hot terminal.

Another experiment.  Power up your pulse motor.  Lock the amperage but let the voltage run as it wishes..  When your motor is up to speed, it will start wanting to use less amps.  At that time, watch your voltage..  You will see your supply's voltage start to climb ever higher.  Some correlate this to more resistance, and I guess that statement is true, but it is incomplete.  Back EMF is "resistance" per-se but the dynamics of wha'ts happening is a little different (and much more interesting) than what adding a resistor does.

bistander

Quote from: Ufopolitics on January 06, 2023, 06:19:41 PM
Hello Bistander,

Sorry to get involved here...but I would like some further explanations as understanding.

I have run a Coil with Two(2) Ohms at 12 Volts and have read over 2.0 Amps...on Pulsed and straight DC.

Doesn't it also depends on the Wire Gauge used, plus the number of turns?

I have also ran 36 plus volts on a Coil of 1 ohm, and have over two(2) and 3 Amps...

None of those values above "make up" for the Ohm Law Formula?

Also, isn't the Ohm Law applicable only to straight (not pulsed) DC Circuits?

On AC, does Ohm Law works as well?

Thanks in advance for your answer(s)


Ufopolitics

Hi Ufo,

Kirchhoff's circuit laws and Ohm's laws apply. Let's see if this pdf will attach.
You will encounter problems when frequency gets high or waveforms deviate far from sinusoid.
I'll also attach a graphic from:
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/acohml.html
Hope that helps.
bi

floodrod

For alternating currents (AC), capacitors and coils are non-ohmic conductors.

non-ohmic conductors do not follow ohms law

bistander

Quote from: floodrod on January 07, 2023, 12:23:39 AM
For alternating currents (AC), capacitors and coils are non-ohmic conductors.

non-ohmic conductors do not follow ohms law

Hi floodrod,
I believe that you refer to impedance in the circuit. The pdf and graphic which I attached in recent reply to Ufo explains this. At lower frequencies and sinusoid waveform, Ohm's Law and Kirchhoff's rules apply using Z in place of R and phasors for V and I. Also PF, power factor is relevant. The math becomes complex, but circuit analysis follows the same principles.
bi

rakarskiy

First, there is no phase shift between current and voltage in the circuit. We take a simple program and see what happens in the usual oscillatory circuit Resistor-Coil-Capacitor.
If a shift exists, it should be on the entire section of the contour on all elements. But it has an interesting picture on the resistor, it is not there, and in the sections of the coil and capacitor, the type of graph corresponds to the current-voltage charge / discharge characteristic for this element. (illustration attachment and link for those interested)
As you can see, there are no current and voltage offsets on the resistor.

Inside the circuit, two graphs on opposite sides of the resistor, this is what we see on the oscillograms and takes it for what we see.

https://tinyurl.com/2f973jxy


Secondly, the primary impulse to the coil will not experience any reactance, since there is still no magnetic field in the coil core and the magnetic permeability of the core material is maximum. As soon as the field appears, the swing will begin. This is explained just by the interaction of the fields of the vortex conductor (and I argue that this is the strength of the current), and the magnetic field of the core. The second reactivity factor is the interturn interaction of currents. A magnetic field is inert (slower) than an electric field. But for the dimension of rotation 90* - 180* - 270* it is impossible to notice this.

Thirdly, for variable oscillation frequencies, the reactance is additionally based on the skin effect in the conductor, also described in the literature. The skin effect just confirms the vortex structure of the electric and magnetic fields around the conductor.

All pleasant discoveries, I left to finish my work.