Holcomb Energy Systems:Breakthrough technology to the world

[kolbacict]

Have you noticed what is really happening inside the stator near the iron pole pieces?
This is when the stator is powered by a three-phase current from the frequency converter, in my case.
I think Holcomb's commutator is also something similar.
What does the electron beam show, because, unlike a squirrel-cage rotor, it has no inertia.
How the beam is smeared, how much dirt, higher harmonics, intermodulations and other things are there, you, the specialists, know better. But these are our losses. I think this should be gotten rid of.
When used as a conventional induction motor, the rotor converts it quite efficiently into mechanical rotation.For rotor this harmonics don't big mentions.But I do not know how it will show itself in our case. If not for the beam, we would never know what is happening in reality.
We think that everything is smooth and smooth there.

[rakarskiy]

Hi rakarskiy,

You must have your own unique interpretation of Kirchhoff's laws.

Also, you say:


1), 2) & 3) must all be numerically equal. There is only one power at the generator terminals.

And the these two equations, seemingly both for the same power:

Where did the 1/2 factor come from?

Obviously we speak different languages. Good luck.
bi

Why did you decide that these values should be equal? They are equal for the ideal state of the "section of the chain"!
You see, they are taken from a real chain, for a certain moment. The moment is not ideal for the simplest circuit with a generator as a source.

As for the power and Kirchhoff's laws, where you saw their application in this version, we have one source with its own internal resistance, and one load with its own resistance.

Coefficient of adjustment by experience, engineering physics, it is real (in fact), not virtual ***.

Take it, go to any site where wind turbines are independently calculated and made and you will see what and how is calculated.
I remind you there is Ohm's Law for a section of a circuit and for a complete circuit. Like the current formula for a complete circuit, virtual (basic) and real.
That's why you have such "misunderstandings".

I = U / R
I = E / (R+r)         
I = (E - U) / (R+r)



*** By the way, the total current should be I = U / R = U / (R + r0) = 10.4 / 4 = 2.6A.
But in fact: I = 1.3A. Ratio: 2.6/1.3 = 2 or 1.3/2.6 = 0.5
So you can derive the coefficient for the AC torque (otherwise the reactive is not taken into account in our calculations)
I see it didn't bother you that Ohm's law is for direct current, but the values from the circuit are with alternating current.


   


 

[kolbacict]

How the beam is smeared, how much dirt, higher harmonics, intermodulations and other things are there,

Because I take a magnet in my hand and rotate it quickly close to the screen.
In this case, the circle line is thin, without blurring and interference.
I can make such a video, but trust me it's true.

[bistander]

Why did you decide that these values should be equal? They are equal for the ideal state of the "section of the chain"!
You see, they are taken from a real chain, for a certain moment. The moment is not ideal for the simplest circuit with a generator as a source.

As for the power and Kirchhoff's laws, where you saw their application in this version, we have one source with its own internal resistance, and one load with its own resistance.

Coefficient of adjustment by experience, engineering physics, it is real (in fact), not virtual ***.

Take it, go to any site where wind turbines are independently calculated and made and you will see what and how is calculated.
I remind you there is Ohm's Law for a section of a circuit and for a complete circuit. Like the current formula for a complete circuit, virtual (basic) and real.
That's why you have such "misunderstandings".

I = U / R
I = E / (R+r)         
I = (E - U) / (R+r)



*** By the way, the total current should be I = U / R = U / (R + r0) = 10.4 / 4 = 2.6A.
But in fact: I = 1.3A. Ratio: 2.6/1.3 = 2 or 1.3/2.6 = 0.5
So you can derive the coefficient for the AC torque (otherwise the reactive is not taken into account in our calculations)
I see it didn't bother you that Ohm's law is for direct current, but the values from the circuit are with alternating current.

Hi rakarskiy,

*** By the way, the total current should be I = U / R = U / (R + r0) = 10.4 / 4 = 2.6A.

After all this BS, you finally see your mistake.
bi

[rakarskiy]

Hi rakarskiy,

After all this BS, you finally see your mistake.
bi

Where did you see a mistake in me? So you calculated the total power based on the values ​​of the resistor load in the alternating current circuit? Ok, you amuse me.

Therefore, it is necessary to determine the power in the circuit at the time of measurement according to the actual voltage and actual current.