Need help with gravity/buoyancy design

[Novus]

I couldn't have explained it any better.

The critical part is that the fluid levels remain the same at the bottom and top positions therefore not impacting V.
At the same time the total volume of fluid is the same at each interval and the weight difference changes from + 60 and -/- 60 at the bottom position to -/- 60 and + 60 at the top allowing for the counter balances on the pulley to keep everything at equilibrium.

[Tarsier_79]

OK, so at least I am on the right track. I was confused at the start mainly because they are called scenario, which I took as meaning 6 different mechanisms.

[Novus]

Probably since english is not my first language.

Hopefully you or someone else can point out the error in the design so we can put this to rest.

[Tarsier_79]

Hi Novus

I did have a little time to look at your design today.

One thing I did notice is that in scenario 3 and 5, your V weight is not counterbalanced as it enters the liquid. Your counterbalance relies on an equal rise in fluid compared to the relative drop in the V weight. I haven't had time to calculate how much of an effect this will have.

[Novus]

Hi Tarsier,
Thanks for looking into this.

One thing I did notice is that in scenario 3 and 5, your V weight is not counterbalanced as it enters the liquid.

As I mentioned before, I didn't as yet share the idea on the counterbalance to keep V weightless.

Your counterbalance relies on an equal rise in fluid compared to the relative drop in the V weight.

The counterbalance doesn't rely on an equal rise in fluid compared to the relative drop in the V weight.

I haven't had time to calculate how much of an effect this will have.

I believe you will find that when using the method to counterbalance V as per the 'Example' given earlier (with the 2nd pulley at twice the distance from the pivot point) you will find a loss equal to the gain in potential gravitational energy of mass M.