Igors switcher (EMF recycler2)

[drspark]

Hi Gezgin, Gyula, Members,

Lastnight I made some measurements of the bulb hot.

Battery 6v lantern type.
Open voltage 6.32v
Bulb on voltage 5.86v
Series current .39A
DVM straight DC 
I guess its rated 2.5w @ 6v

drSpark

[drspark]

Hi People

Here is a photo of the circuit, bulbs with 10ohm resisters in parallel.
The resister does not burn connected this way.

9.9v 324hz

drSpark

[gezgin]

Hi drspark,
what about your self running circuit (emf recycler 3.0) with transformer&mosfets.
I tried (with relays) but didnt work.
scop show coil emf picks but when connecting load its disappearing.
Here is gnd to capasitor wave photo:

[hartiberlin]

Hi Dr. Spark,
sorry for the late reply, but I was busy with other work.

It seems from your  scope shot IMG_5942a.jpg picture,
that if you fold the spikes down to the waveform,
that you have about 4 Volts steady of voltage at R1= 100 Ohm,so
that means an input current of about 40 mA.
That means at a voltage supply of about 10 Volts you
have an input power of around 0.4 Watts.

Now the question is , is the bulb glowing brighter than 0.24 Watts ?
Already at the R1= 100 Ohm resistor you "destroy" about U^2/100 Ohm= 0.16 Watts,
so you have left around 0.4 Watts - 0.16 Watts= 0.24 Watts for the bulb).
(Neglecting the other circuit components,
which have much lower currents..)

From the Scopeshot at the bulb it is hard to say.
I would say, if you fold again the waveform, so it
shows a steady line, this line would probably only have around 1 Volts.
Now the question is, what exact resistance your glowing bulb has...

You should better test this with a normal temperature stable
resistor, as the bulb probably has a resistance of about 10 Ohms or more,
if it is glowing.

Maybe you can do a comparison and test with a DC power supply the same
bulb at the same brightness and measure voltage and current and
tell us, how many Watts does it take to glow this bright as in the scope shots you posted.
Also please measure the dc resistance in this operating point in the DC case of your
bulb filament.

So if the bulb would have 10 Ohms resistance, if it is glwoing like this,
then you would have about (1Volt) ^2 / 10 Ohms= 0.1 Watts of power
generated at the bulb,
but if it only would be 2 Ohms, then you would get (1Volt) ^2 / 2 Ohms= 0.5 Watts,
then you would have Overunity.

Regards, Stefan.

[hartiberlin]

Hi Dr. Spark,
please repeat the scope measurements with
2 normal resistors instead of resistor and the bulb:
R1= 100 Ohm 1 Watt type or more
R2= 1 Ohm   5 Watt type or more
and post the scopeshots again at these resistors.

Then we can exactly say, if your circuit is overunity.

Many thanks.