Newman now runs its 7500 pounds motor solely on solarcells !

[Dingus Mungus]

After further review I'm slightly concerned by the numbers now...

Basically its descibed load is 5000gallons in 10 hours. (appox 9gpm)
The described solar power source is capable of 120w max.

Go and crunch the numbers against pumps designed to do this.
http://www.plumbingsupply.com/performancepropumps.html
It says that pump will move 100% more water at the same wattage.

Anyone else slightly confused by this?

~Dingus Mungus

[ChileanOne]

Hello Dingus:

The calculus I have seen and I have done say that the work done is around 20 to 30 watts, so I guess that what poor old Joseph has is a very unefficient and massive way to pump water wasting otherwise more useful solar power.

[hartiberlin]

Hmm,
so let?s try to calculate,how much power it needs to move how much water
up 10 Foot ( 3 Meters) in one second ...

Okay, Newman says in the video he is moving up 9 gallons of water (about 34 Liters)
in a minute 10 foot up.

So now to move 1 Kg = 1 Liter of water up 3 Meters ( 10 foot ) you need a work energy W
of:
W= mass x earth gravitational acceleration x height.
So W=  1 Liter x 9.81 x 3 Meters= 29.43 Wattseconds ( Joule)

So if you want to bring up every second 1 Liter = 1 Kg of water 3 Meters up you need
a Wattage of 29.43 Wattseconds / 1 Second= 29.43 Watts.

Now Joe is pumping 9 gallons per minute, that is 34 Liters per minute and divided
by 60 to get a value per second :
34 Liters/minute  / 60 = 0.5666 Liters/second.

So Joe is pumping just 0.5666 Liters/second 3 Meters up.

So as it is less than 1 Liters per minute we must multiply the
29.43 Watts x 0.5666  and thus get 16.68 Watts.

So we only need 16.68 Watts contant power input to pump up
the same volume of water Joe is pumping up, if we would have
a 100 % efficient electrical to mechanical conversion pumping system.

Now Joe needs about 120 Watts of power for this.
So it seems his system is pretty inefficient to do this job.

But you never know, how much losses his system has
internally, e.g. how much energy goes into heating
his coil, how much enery is lost in turning the gears,
how much energy is lost inside his pump as friction...
Hmm... So as I said before, the mechanical output of
the Newman motors is less than the inputed electrical energy.

I don?t understand, why Joe Newman does not see this

He should better try to enhance his machine in putting out more RF
power and light bulbs with it as he has done with his earlier machines...
The real strength in his machine is the RF power output via the sparks
and the DC component energy spike with the bigger coil machines.
But mechanically they are only around 60 to 70 % efficient I guess.

Regards, Stefan.

[maxc]

The more RF per rotation the more chance that extra power by transmutation.

I've been reviewing Newman's old right-up he put a short out segment on the commutator to reduce  "wasteful sparking" But he has many different commutator
setups. One fired 28Xper rotation. I'm building one out of tungsten firing 22X per rotation.
I think he found out later what was happening. I'll read some more.

I'm having problems downloading anything off Newman's site, problems staying logged on and posting here as well

[Dingus Mungus]

So then the question remains:
Why would Joeseph Newman make this a demo???

I'm sure he realizes that the pump is not efficient, but what about the device is going to provide this excess energy. I would assume he has something up his sleeve, but I can't imagine what... Unless maybe the pump is also a heater that brings the output temp up high enough to signify a Cop>1. Who knows though... I'll go to the demo if it still happens and see what I can find out.

~Dingus Mungus