How this was done in 1821.....

[Paul-R]

@steve_whiss,

The ?Faraday? part of the job has already been done as far as overunity goes?production of excess energy and violation of CoE has been proven beyond doubt in SMOT.

The simple question is this, if SMOT is over unity, why hasn't anyone ever closed the loop? 

In truth, despite tremendous effort, no one has ever closed a SMOT loop, and no one ever will.

What is your proof for this statement?

A SMOT ramp gives extra potential energy (at the rate of MxGxH) to the ball.
The energy equation clearly indicates OU. The fact that the idea has not been
turned into a circle yet does not mean that this will not happen tomorrow.
Paul.

[bitRAKE]

Typing an equation doesn't make it true. A test needs to measure input and output energy to determine if there is a gain from the SMOT - no such test has been presented and the analysis here is incomplete.

[Omnibus]

@bitRAKE,

[quoe]Typing an equation doesn't make it true. A test needs to measure input and output energy to determine if there is a gain from the SMOT - no such test has been presented and the analysis here is incomplete.[/quote]
A test measuring input and input energy which clearly determines the gain from SMOT is made. The equations presented reflect that. You don?t understand that and continue to fill the forum with nonsense.

[bitRAKE]

@Omnibus, the nonsense is your conversion of input energy - which hasn't been measured. Some measurements of output energy have been made (ex. http://jnaudin.free.fr/html/smotidx.htm ). Using your rational one could say a door hinge is OU. Your equations reflect nonsense.

[Omnibus]

@bitRAKE,

@Omnibus, the nonsense is your conversion of input energy - which hasn't been measured. Some measurements of output energy have been made (ex. http://jnaudin.free.fr/html/smotidx.htm ). Using your rational one could say a door hinge is OU. Your equations reflect nonsense.

You?re continuing with your nonsense. The input energy is mgh1 (in fact, it is less than mgh1 and is mgh1 ? (Ma ? Mb). The output energy is mgh1 + mgh2 + [kinetic + ?].

mgh1 < mgh1 + mgh2 + [kinetic  + ?]

input_energy < output_energy

Both input and output energy are measured since to measure heights h1 and h2 as well as m is straightforward (g is a constant) and [kinetic + ?] is always greater than zero.

If the input energy when lifting a ball from the floor to the table at height h1 is not mgh1 and the output energy when the ball falls back to the floor is not mgh1 then CoE will be violated any moment. It?s not. In lifting the ball from the floor to the table and then letting the ball fall back on the floor CoE isn?t violated.

CoE, however, is violated in SMOT, as I?ve shown.

You don?t understand the above and continue to fill the forum with nonsense.