The Lee-Tseung Lead Out Theory

[M@rcel]

Just to stir things up a little 

http://www.wipo.int/pctdb/en/wo.jsp?wo=2006077451

Lawrence,

In your reply to the written opinion ( http://www.wipo.int/ipdl/IPDL-IMAGES/PATENTSCOPE/74/32/bd/0032bd.pdf ), you mention some video's. Are they available for us?

[Top Gun]

Maybe what would be helpful is to use actual numbers, instead of units.  So, if you want to convince us "laymen", please show an analysis that has the following:

1.  Mass of bob, in kilograms.
2.  Length of string, in meters or centimeters
3.  Horizontal force applied, in Newtons
4.  Distance the bob moves vertically and horizontally, in meters or centimeters

I think with the above, even we, the untrained, can figure out how much work is done and indeed whether two parts input results in three parts output.

I shall answer for Mr. Tseung.  Let us assume that
(1)   The mass of bob M is 60 kg.  The gravitational force (weight) = Mg. The value of g, the gravitational constant is 9.8 meter/sec/sec.  Thus the gravitational force = 60 x 9.8 = 588 newtons.
(2)   The length of string is 1 meter
(3)   The horizontal force is 1/6 that of the weight. This will be consistent with our slide 11.  Thus the horizontal force is 588/6 = 98 newtons.
(4)   The angle a remains the same and obeys the relationship tan(a) = F/Mg.  From the tables or the calculator or the spreadsheet, a is determined to be 9.46 degrees.
(5)   The horizontal displacement dX = Lsin(a) = 1 x sin(9.46) = 0.16436 meters
(6)   The vertical displacement dH = L x (1-cos(a)) = 1 x (1-0.9864) =0.0136 meters
(7)   The horizontal work done = horizontal force x dX = 98 x 0.16436 = 16.10728 Joules
(8 )   The vertical work done = vertical force x dH = 588 x 0.0136 =8.133 Joules
(9)   The ratio of horizontal/vertical work = 16.10728/8.133 = 2.014

The Input Lee-Tseung Energy is item (7).  The total output energy is (7) +(8 ).
The COP or (total output energy / Input energy ) = (16.10728 + 8.133)/16.10728 =1.496471 = 1.5 approximately.

Hope that helps.

[Koen1]

Are you really sayingthat any pendulum always shows a 150% efficiency?
Then why don't all pendulums fly apart from all the excess energy they
produce but cannot release?

And, just a quick remark in between acts, to get output, there should
be a mechanism for actually extracting the energy from the device,
right?
Otherwise, there is simply no output.
Where is the mechanism? How do you transform this claimed overunity
kinetic energy into actual usefull (electrical?) energy?
And how efficient is your conversion process?

And yes, where are the videos, Tseung?
Anyone can apply for and even get a patent,
does not mean the idea really works.

By the way, I thought you were located in Hong Kong, Tseung?
You have said so repeatedly.
Then why is it that the residential address on the patent application
is one in California?
Can you teleport as well now?

[ltseung888]

Just to stir things up a little 

http://www.wipo.int/pctdb/en/wo.jsp?wo=2006077451

Lawrence,

In your reply to the written opinion ( http://www.wipo.int/ipdl/IPDL-IMAGES/PATENTSCOPE/74/32/bd/0032bd.pdf ), you mention some video's. Are they available for us?

Dear M@rcel,

I am focusing on the discussion of Slides 10-12 at present.  All other questions will be deferred. 

Please comment on Slides 10-12.  Can you follow them?  Do you agree that they are correct in both mathematics and physics?

[ltseung888]

Are you really saying that any pendulum always shows a 150% efficiency?
Then why don't all pendulums fly apart from all the excess energy they
produce but cannot release? ?.

Dear Koen1,

The Lee-Tseung theory uses the example of applying Lee-Tseung Pulls or Pulses on a simple pendulum to Lead Out gravitational energy.  Energy is Lead Out during the application of such Lee-Tseung Pulls.

Please try to follow the mathematics and physics discussions in Slides 10-12.  I deal with comments on these slides only.  All other comments will be deferred.