The Lee-Tseung Lead Out Theory

[utilitarian]

(4)   However, whenever the tension of the string is involved, we have to consider whether (a) does the tension in the string represent a force? (b) does this force has displacement in direction of the force?  Gravity does work and imparts energy via the tension in the string.

(a) Yes, the string has tension, but (b) no, there is no displacement along the direction of that force (toward the pivot), so there is no work done there and no energy imparted.

[Kul_ash]

It is clear that (1) and (2) are different. 
Or Mg x dH is not equal to F x (dH+dX).

You are repeating yourself now.  Please break out of this loop.

1.  Work equals force times distance, correct?
2.  The bob did not move straight up, correct? 
3.  The bob moved in a circular arc, correct?
4.  Multiply force times the length of the arc, and you will get the total work done by the pulse force.  Correct?

Then you can compare that to mgh where m=mass of bob.

Why is this so hard?  ***Integral calculus is never easy.

Dear utilitarian,

1.  Work equals force times distance, correct?
     Correct if vector mathematics used.

2.  The bob did not move straight up, correct? 
     Correct

3.  The bob moved in a circular arc, correct?
     Correct but the motion is not at constant velocity.  It accelerates at the beginning and decelerates at the end - to a complete stop at Position  B.

4.  Multiply force times the length of the arc, and you will get the total work done by the pulse force.  Correct?  Incorrect!!!

Both Force and Displacement are vector quantities.  You have to consider their directions.  The correct mathematical representation should be

The integral of F.ds  from point A to point B. 

Note the dot notation.  The general form of this integral says that F can be any function (need not be constant in magnitude or direction) and ds is an infinitely small increment.  The path can be anything - not necessarily an arc.  The general form is indeterminate.  We have to know the actual F function and the actual path before we can work out this integral.

In other words, we can have different functions of F and we can get different results of work done even though the path is an arc.  Different work means different energy.  The more advanced form of mathematics and physics says that even though the bob moves from Point A to Point B, different work (or different energy) can be involved.

Am I confusing all the forum members who have no formal training in integral calculus???

Two Points confused me totally:
You said:
"The bob moved in a circular arc, correct?
     Correct but the motion is not at constant velocity.  It accelerates at the beginning and decelerates at the end - to a complete stop at Position  B."

If contant force is applied, then how come velocity reduces in its path? You are "forcing" pendulum to move. If pendulum is moving on its own converting PE and KE into each other then yes, velocity is not constant. But you are treating your pendulum as a "simple pendulum" and "forced pendulum" at the same time. How is that possible? How a body becomes stationary when force is still applied to it? PE will be max only when the work done by lifting force is over i.e. when KE becomes zero. In all other stages, it will have KE and PE balancing total energy of the system. If you open any book it always have three chapters on pendulum motion. They are simple pendulum, damped pendulum and forced pendulum. All have different sets of motion equations. How can you apply two sets of eqations to one problem? Please explain.

Second Point: You said:

The integral of F.ds  from point A to point B. 

Note the dot notation.  The general form of this integral says that F can be any function (need not be constant in magnitude or direction) and ds is an infinitely small increment.  The path can be anything - not necessarily an arc.  The general form is indeterminate.  We have to know the actual F function and the actual path before we can work out this integral.

In other words, we can have different functions of F and we can get different results of work done even though the path is an arc.  Different work means different energy.  The more advanced form of mathematics and physics says that even though the bob moves from Point A to Point B, different work (or different energy) can be involved.

Yes it is true! But then my friend it is not simple hamonic motion, is it? We are talking about pendulum in resonance and pendulum motion. You can pull bob any way you want but the moment it gets out of its orbit and behaves erratic, it is not simple harmonic motion any more. So are you telling me to apply totally different type of motion in this case? And if you are what it is? How a system will come in resonance if it does not follow SHM and follos chaotic motion? In other words, you are damping pendulum's natural oscillations with your erratic pull. Is that a Tseung pull? Please explain.

[Kul_ash]

@ top gun

In other words, in your first statement, you admitted that bob went up in a circular motion and in second you said it need not go in circular motion and the path is indeterminable! 

Are you really sure about what you are talking about even before getting in to integral calculus? Make your mind on which one of the above is true, then we will continue discussion further.

[ltseung888]

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http://www.ccecn.com/User/u9457.html
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My translation (may not be the official terms) on the website:
http://www.ccecn.com/User/u9457.html

ä¸â€"ç•Å'生产率科学联盟中国分会
The World Productivity Alliance (China Branch)

联系人： 王沈河      秘书长
Contact Person: Wang Shum Ho  - Secretariat
详细åÅ"°åâ,¬Ã¯Â¼Å¡ 中国?辽宁çÅ"?沈阳市 
Address: Shum Yang City, Li Ling Province, China
电话： 86-24-24186088    手æÅ"ºï¼š 13066636868
Phone: 86-24-24186088  Mobile: 13066636868
ä¼ çÅ"Ÿï¼š 86-24-24186088
Fax: 86-24-24186088
网åâ,¬Ã¯Â¼Å¡ http://
Website: not available
Email： daiyx@pub.sdsti.net.cn
主营è¡Å'业： 石油 Ã¥Å'â€"å·¥ å¡‘æâ€"â,,¢ æ©¡èÆ'¶ ç…¤åÅ'â€"å·¥
Main line of Business:
Oil, Chemicals, Plastics, Rubber and Coal related industries

You can call him directly.  He has secretaries who can speak English.

[Kul_ash]

Am I confusing all the forum members who have no formal training in integral calculus???

I think you are confusing us with so many contradicting assumptions. Integral calculus shall come way late in picture:

1. Motion is circular at the same time need not be circular and indeterminate
2. Pendulum follows SHM at the same time need not follow SHM
3. Force is constant at the same time it can vary in magnitude and direction.
4. Resulting force is outwards but the motion is circular
5. Constant Force is still applied but velocity is constantly decreasing and at one stage even when force is still there, velocity becomes zero. So PE is max at the sam time still external force is applied.
6. Length is altered because of force applied on some where on string, but the length considered in calculations is still the same.
7. 10 million experiments conducted but not a single one is documented.

I wish to discuss your theory really on Physics and mathematics but if this is the way of your explanation, then how is that possible to talk technically?