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Overunity Machines Forum



The Lee-Tseung Lead Out Theory

Started by ltseung888, July 20, 2007, 02:43:44 AM

Previous topic - Next topic

0 Members and 44 Guests are viewing this topic.

shruggedatlas

Pendulum8 looks correct, at least the math looks like it would work out if you were exerting force on the bob itself.  (I think it is the same math from before.)  I am not sure what the ramification is from putting the force farther up the string.  But I am not saying it's not right.  It's probably right.  Assuming a massless string, it should not matter where you apply the force.  I am not going to get a calculator out now.

To note, Kul_Ash has a very valid point.  If you apply the horizontal force, it stops being horizontal as soon as the bob moves.  At that point, the force you apply will have a horizontal and vertical component.  It must, because the string forces the bob to change direction.

ltseung888

Dear All,

Many may be asking what has happened to Wang Shum Ho and his Electricity Generator.  Please see the following websites:

http://www.ccecn.com/User/u9457.html
http://www.baidu.com/s?wd=%CD%F5%C9%F2%BA%D3

He is no longer an "unknown" in China or worldwide.  He represented China as a top energy expert in the "Asian Economic Summit" in Hainan Island last week.  He will represent China again in the World Productivity Conference in South Africa later this year.

His title, contact address, email and telephone numbers are publicly disclosed.  I no longer need to promote him or his machine.
Compressible Fluids are Mechanical Energy Carriers. Air is not a fuel but is an energy carrier. (See reply 1097)
Gravitational or Electron Motion Energy can be Lead Out via oscillation, vibration, rotation or flux change systems.  We need to apply pulse force (Lee-Tseung Pulls) at the right time. (See reply 1106 and 2621)
1150 describes the Flying Saucer.  This will provide incredible prosperity.  Beware of the potential destructive powers.

chrisC

Quote from: ltseung888 on April 19, 2008, 05:39:30 PM
Dear All,

Many may be asking what has happened to Wang Shum Ho and his Electricity Generator.  Please see the following websites:

http://www.ccecn.com/User/u9457.html
http://www.baidu.com/s?wd=%CD%F5%C9%F2%BA%D3

He is no longer an "unknown" in China or worldwide.  He represented China as a top energy expert in the "Asian Economic Summit" in Hainan Island last week.  He will represent China again in the World Productivity Conference in South Africa later this year.

His title, contact address, email and telephone numbers are publicly disclosed.  I no longer need to promote him or his machine.


Tell us where in this link
http://www.ccecn.com/User/u9457.html
does it mention anything about the so called Wang generator?
Isn't this a web site of some Chinese company offering chemical, utilities and communications services?

Is this another one of your make believe proverbial crap? Whether Wang's other interest includes the above services has nothing to do with your great imagination of the implementation of this wonderful Lee-Tseung lead-out crap theory!

Don't you know when to quit?

cheers
chrisC



Top Gun

Quote from: shruggedatlas on April 19, 2008, 05:08:57 PM
Pendulum8 looks correct, at least the math looks like it would work out if you were exerting force on the bob itself.  (I think it is the same math from before.)  I am not sure what the ramification is from putting the force farther up the string.  But I am not saying it's not right.  It's probably right.  Assuming a massless string, it should not matter where you apply the force.  I am not going to get a calculator out now.

To note, Kul_Ash has a very valid point.  If you apply the horizontal force, it stops being horizontal as soon as the bob moves.  At that point, the force you apply will have a horizontal and vertical component.  It must, because the string forces the bob to change direction.

Dear shruggedatlas,

Thank you for your comments.  Pendulum08.jpg is indeed 100%  correct.

You also raised the valid point from Kul_ash.  I modified pendulum08.jpg to pendulum12.jpg to show that the supplied, constant F need not be horizontal until the final position.  The vertical work done by this constant force F is F x dH. (or 10 x dH Units).  This is only one sixth of the increased vertical potential energy (= mgh = Mg x dH = 60 x dH units).

Where does the remaining 50 x dH units of vertical energy come from???

The only logical physics explanation is - from gravity via the tension of the string!!!

Pirate88179

I am sorry but you people just don't get it.  You have to apply the continuous pulse, which translated means, the regularly intermittent constant force...don't you get it?

Bill
See the Joule thief Circuit Diagrams, etc. topic here:
http://www.overunity.com/index.php?topic=6942.0;topicseen