Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Over Unity NOT Achieved!!!

Started by oouthere, July 21, 2007, 04:41:21 PM

Previous topic - Next topic

0 Members and 1 Guest are viewing this topic.

RunningBare





Point, the speed of the alternator, the faster a magnet sweeps past a coil the higher the frequency change, the higher the frequency change the higher the coil reactance(look it up) the higher the reactance the less load it can supply, reactance is loosly the AC equivelant of DC resistance(look it up).

reactance is also where a lot of accounting errors take place, you cannot calculate reactance in the same way as resistance since current lags voltage by 90 degrees in a coil and current leads voltage by 90 degrees in a capacitor.


oouthere

I will not argue that!

It's just when something says 270VAC @ .35 amps (94.5 VA) is going across a 110VAC light bulb (measured with both a DMM and o'scope) and the light is not burning brightly obviously something is amiss.  You can plug the same bulb directly into the wall at 120VAC and it will burn many times brighter.  The SM device is pulsing at 5Khz/875VDC with 10 bulbs which is well below their intended voltage and much above their intended frequency.....the same as the RV setup except the SM bulbs are really bright and the RV's is extremely dull.

Rich

RunningBare

Quote from: oouthere on August 10, 2007, 04:18:58 PM
I will not argue that!

It's just when something says 270VAC @ .35 amps (94.5 VA) is going across a 110VAC light bulb (measured with both a DMM and o'scope) and the light is not burning brightly obviously something is amiss.  You can plug the same bulb directly into the wall at 120VAC and it will burn many times brighter.  The SM device is pulsing at 5Khz/875VDC with 10 bulbs which is well below their intended voltage and much above their intended frequency.....the same as the RV setup except the SM bulbs are really bright and the RV's is extremely dull.

Rich
I understand the confusion, but not difficult to explain
There are high frequency componants that the meter and scope will be picking up, you have to consider time also, I can pulse a 120 volt lamp with 1000 volts and not have it burn out, simply by making sure that the 1000 volt pulse is very short in duration, in other words not on long enough to push the lamp filament past it's stress point.

oouthere

Indeed, I understand what you are saying but the input wave into the light bulb is a perfect sine wave and a little over 100hz.  That would easily be enough to light the bulb fully imo if all of the potential were indeed current carrying potential.  The only reason I'm making the video is to show that only a small percentage (less than 20% calculated in my case) is actual current carrying voltage.

Rich

RunningBare

Quote from: oouthere on August 10, 2007, 05:30:54 PM
Indeed, I understand what you are saying but the input wave into the light bulb is a perfect sine wave and a little over 100hz.  That would easily be enough to light the bulb fully imo if all of the potential were indeed current carrying potential.  The only reason I'm making the video is to show that only a small percentage (less than 20% calculated in my case) is actual current carrying voltage.

Rich

At a guess I would say that most of what your measuring is actually returning to the excitation coils in the alternator, but alternators are not my speciality.