Stanley Meyer replication with low input power

[ravzz]

Not just that even the link you posted has been removed by the user!! I saw it a little while ago1

Whats Happening?



'Water Fuel Cell blast' was the name of the video on youtube.

Description of the video:
120v to 25v step down transformer, primary amp pull AC .80 amps. Secondary DC pull 3 amps. Heat issue if ran over 1 min.

The generation in both the videos looked the same except that he shows the amp meter showing around 0.82 Amps.


You could visit his forum postings on the link after yours.


Ravi

[ravzz]

The link to hydrocars postings forum is

http://waterfuelcell.org/phpBB2/viewtopic.php?t=454

[NerzhDishual]

@Harti_Berlin

Do you mean 2.4 Ampere/hour?

2 moles of electrons for one mole (22.4 liter) of H2.
2*96500= 193000 coulomb for 22.4 liters.
193000/3600/22.4 = 2.4 amp/hour for one liter.

You need more than one volt (theorically 1.23 volts but in practice almost 1.6 volts). This 'leads out' to about 2.4* 1.6 =/= 4 watts/hour for one liter (or 4 kWh per cubic meter) of h2.  Leads it out not?

According to Kanarev:

"The most modern Electrolyzers consume 4.0 kWh per cubic meter of this gas.
Electrolysis process takes place by voltage of 1.6-2.0 V and current strength of
dozens and hundreds of amperes. When one cubic meter of hydrogen is burnt, 3.55
kWh of energy is released."

http://www.guns.connect.fi/innoplaza/energy/story/Kanarev/electrolysis/index.html


BTW: This is not a skeptic remark. I'm convinced  that COP >1 ('overunity') electrolysis is possible.

Best

[ravzz]

Faraday's is 2.4 watts / hour / liter.


Volts x Amps = Watts

12 x 0.51 = 6.12 watts
the generation is around 7 cc/sec of H2 + O2

This converts to 4.66 CC of H2/sec

which converts to 16.776 Lits / hour

16.776 x 2.4 watts (Faraday/lit/hour generation) = 40.262 Watts


Well I seem to be generating the equivalent of 40.2 watts as per Faraday with just 6.12 Watts.........I hope this answers Kumaran's question aswell.

I dont know if im right but I seem to be generating 550% excess

as the above works out to 40.2/6.12 x 100 = 656.86%

656.86 - 100 (Faraday) = 556.86% OU !!

Correct me if im wrong with the calculations.



I remember watching on one of Stan Meyer Videos where they mention the Output to be over 1700% faradays....I guess there's more work needed to be done in this direction.

Dave's unit was 250% OU mine looks a little higher....one of the reasons I think is because my unit is comparitively bigger 9" length 9 tubes compared to Dave's 5" length 6 tubes. Stans was 18"length 9 tubes...double the size of my WFC.

Another reason for higher efficiency could be Dave's gap between the tubes was 1/16" or 1.5875 mm and mine was lesser at less than 0.670 mm....calculations posted by Stefan above.


{For pictures of the Pipe sizes check next page, the pics were posted on 25th Aug 2007.}



I'm using individual leads to each pipe in the WFC.

these I remember now. will post if I remember some more.

Ravi

[rapttor]

@rapttor

in this thread it gets explained! (from the creator himself)
http://waterfuelcell.org/phpBB2/viewtopic.php?t=454

@ unicron, I know... I was specifying someone in particular who I see has remained silent, no big deal, thanks for the reply.

-rapttor